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love history [14]
2 years ago
12

Eeeeeeeeeeeeeeeweeeeeeeeeeeeeeeeee

Mathematics
1 answer:
Vladimir [108]2 years ago
5 0
This is a rational number due to the negative in front of the ratio
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What belongs in the box marked with the question mark in the proof?
koban [17]
<span>the blank boxes are for you to plug in x=20 to prove its right. so it would be 3(20)-4=2(20+8) 60-4=2(28) 56=56 so its true!</span>
6 0
3 years ago
Please help me please help me please help me please help me please help me please help me please​
Serga [27]

Answer:

first one is square root

don't know the second tho

4 0
2 years ago
Given the function f(x) = 4(2)x, section a is from x = 1 to x = 2 and section b is from x = 3 to x = 4. part
Aliun [14]
A. Average rate of change for x=1 to 2: 4(2²)-4(2)=16-8=8; from x=3 to 4: 4(2⁴)-4(2³)=64-32=32.
b. Section b is 32/8=4 times greater. As the exponent of 2 increases, the gaps between consecutive powers of 2 gets wider and therefore the rate of change is greater.
6 0
3 years ago
Write a recursive formula for each sequence.<br> 2,20, 200, 2000, ...
Brut [27]

Answer:

1,2

Step-by-step explanation:

6 0
3 years ago
The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.
denis-greek [22]
\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b

which means there is some integer k for which a+b=9k.


Because 9\mid a and 9\mid b, there are integers n_1,n_2 such that a=9n_1 and b=9n_2, and


\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42

We have 42=2\cdot3\cdot7, which means there are four possible choices of n_1,n_2:

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for a,b:

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of a+b is 117.
6 0
3 years ago
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