Answer:
792600
Step-by-step explanation:
For this question you can add four zeroes to the back of 792.6 andmove the decimal to get you the answer, hope this helps
It's also good to know that if the exponent was positive the answer would be 0.07926
Answer:y=-1/4x+3
Step by step explanation: i cant explain it
The centre is the median of the data, so the middle number. IT can also be the mean which is the average.
The spread tells you about the rang of the data.
The shape describes the different types of graphs you get if you graph the data so it could be symmetric or skewed etc. The different shapes tell you different things. For example, a skewed graph might tell you people prefer a certain option.
The answer is: 3.91 inches .
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Note: Volume of cylinder: V = (base area) * (height);
in which: V = volume = 384 in.³ ;
h = height = 8 in. ;
Base area = area of the base (that is; "circle") = π r² ;
in which; "r" = radius;
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Solve for "r" :
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V = π r² * (8 in.) ;
384 in.³ = (8 in.) * (π r²) ;
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Divide EACH SIDE of the equation by "8" ;
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(384 in.³) / 8 = [ (8 in.) * (π r²) in.] / 8 ;
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to get:
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48 in.³ = (π r²) in.² * in. ;
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↔ (π r²) in.² * in. = 48 in.³ ;
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Rewrite this equation; using "3.14" as an approximation for: π ;
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(3.14 * r²) in.² * in. = 48 in.³
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Divide EACH SIDE of the equation by:
"[(3.14)*(in.²)*(in.)]" ; to isolate "r² " on one side of the equation;
(since we want to solve for "r") ;
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→ [(3.14 * r²) in.² * in.] / [(3.14)*(in.²)*(in.)] = 48 in.³ / [(3.14)*(in.²)*(in.)] ;
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→ to get: r² = 48/3.14 ;
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→ r² = 15.2866242038216561 ;
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To solve for "r" (the radius; take the "positive square root" of EACH side of the equation:
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→ +√(r²) = +√(15.2866242038216561)
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→ r = 3.9098112747064475286 ; round to 3.91 inches .
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First add 14+2 so you have sqrt(x) +14=x. Next subtract the 14 to the other side and square both sides, so you have x=x^2+28x+196. Now subtract the x, then use quadratic formula to get the two solutions for the way you have the question typed. However, since I recognize this as being a test question from your FLVS course that is not typed correctly with the parenthesis that will give you the wrong answer. A better idea would be to review through the examples in the lesson, try a few practice problems, then you can easily solve by isolating the square root on one side by itself, then squaring both sides.