Part A is 12.
Part B is 17.
Answer:
The estimate is ![P__{hat}} \pm E = 0.37 \pm 0.0348](https://tex.z-dn.net/?f=P__%7Bhat%7D%7D%20%5Cpm%20E%20%20%3D%200.37%20%5Cpm%200.0348)
Step-by-step explanation:
From the question we are told that
The sample size is n = 522
The sample proportion of students would like to talk about school is ![\r p__{hat}} = 0.37](https://tex.z-dn.net/?f=%5Cr%20p__%7Bhat%7D%7D%20%3D%20%200.37)
Given that the confidence level is 90 % then the level of significance can be mathematically evaluated as
![\alpha = 100 - 90](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%20100%20-%2090)
![\alpha = 10\%](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%2010%5C%25)
![\alpha = 0.10](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%200.10)
Next we obtain the critical value of
from the normal distribution table, the value is
![Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } = 1.645](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%3DZ_%7B%5Cfrac%7B0.10%7D%7B2%7D%20%7D%20%3D%20%201.645)
Generally the margin of error can be mathematically represented as
![E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }](https://tex.z-dn.net/?f=E%20%3D%20%20Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%2A%20%20%5Csqrt%7B%5Cfrac%7B%5Cr%20P_%7Bhat%7D%281-%20%5Cr%20P_%7Bhat%7D%20%29%7D%7Bn%20%7D%20%7D)
=> ![E = 1.645 * \sqrt{\frac{0.37 (1- 0.37 )}{522 } }](https://tex.z-dn.net/?f=E%20%3D%201.645%20%2A%20%20%5Csqrt%7B%5Cfrac%7B0.37%20%281-%200.37%20%20%29%7D%7B522%20%7D%20%7D)
=> ![E = 0.0348](https://tex.z-dn.net/?f=E%20%3D%200.0348)
Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is
![P__{hat}} \pm E](https://tex.z-dn.net/?f=P__%7Bhat%7D%7D%20%5Cpm%20%20E)
substituting values
![0.37 \pm 0.0348](https://tex.z-dn.net/?f=0.37%20%5Cpm%200.0348)
Given
Tom and Martin both worked 9 hours this week and sold $360 worth of meals
Tom's percent of tips was 15% while Martin's was 20%
Find out the most money this week between Tom and Martin
To proof
In this question take two cases
FIRST CASE
Martin worked 9 hours
sold worth of meals = $360
Martin's percent of tip = 20%
First convert 20% in decimal form
= ![\frac{20}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B100%7D)
= 0.20
than the equation becomes
Martin makes money = 9 × 2.50 + 0.20 × 360
= 22.5 + 72
= $ 94.5
SECOND CASE
Tom worked 9 hours
Tom's percent of tips = 15%
sold worth of meals = $360
First 15 % is written in decimal form
= ![\frac{15}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B100%7D)
= 0.15
than the equation becomes
Tom makes money = 9 × 2.15 + 0 .15× 360
= 19.35 + 54
= $ 73.35
Thus martin makes money is $94.5
Thus tom makes money is $73.35
Hence Martin makes more money than tom
Hence proved
Answer:
Kappa
Step-by-step explanation:
Mochi weighed 1 pound when he was born, and Kappa weighed 2 pounds when he was born. Therefore, Kappa is the answer.
Answer:
4.5 lb
Step-by-step explanation:
225/50 = 4.5 lb
Check work: 4.5 * 50 = 225 lb