Answer: Area = x² + 6x + 8
Step-by-step explanation:
Area = length x width
Area = (x+2)(x+4)
Area = (x)(x) + (x)(4) + (2)(x) + (2)(4)
Area = x² + 4x + 2x + 8
Area = x² + 6x + 8
Answer:
B) AAS
Step-by-step explanation:
B) AAS
Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?
