<span>The answer to this question is c, two. The top arc of the circle intersects the y=x^2 as each 'limb' extends into infinity. The part of the circle below the x-axis does not intersect the circle. The y=x^2 curve does not dip below the x-axis, but does extend into infinity on both the negative x-axis and positive x-axis.</span>
It should be represented into a Jorge
9514 1404 393
Answer:
(a) x^2/16 +y^2/9 = 1
Step-by-step explanation:
The form for the equation of an ellipse centered at the origin is ...
(x/(semi-x-axis))^2 +(y/(semi-y-axis))^2 = 1
The vertex values tell you the semi-x-axis is 4 units, and the semi-y-axis is 3 units. Then you have ...
(x/4)^2 +(y/3)^2 = 1
x^2/16 +y^2/9 = 1
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In case you don't remember that form, you can try any of the points in the equations. The equation that works will quickly become apparent.
Answer:
x=5 x = -3
Step-by-step explanation:
-7 / ( x^2 -2x -15)
Factor the denominator
-7
----
(x-5) ( x+3)
The excluded values are when the denominator is equal to zero
(x-5) (x+3) =0
x-5 =0 x+3=0
x=5 x = -3
Okay, here we have this:
Considering the provided information, we are going to calculate the requested value, so we obtain the following:
Then we will substitute in the following formula:
Students who play soccer=Number of students*(Probability that they play soccer)
Replacing:
Students who play soccer=300*(12/25)
Students who play soccer=3600/25
Students who play soccer=144
Finally we obtain that 144 students would we expect to play soccer, based on Sean's experiment.
