What is the degree of the expression 3x^2?

VIIIe in the standard (x,y) coordmate pralit nas

Savatey [412]

The coordinates of point B are (-4 , -2) ⇒ answer H

Step-by-step explanation:

In any circle

The diameter of the circle passing through its center
The center of the circle is the mid-point of all diameters

If (x , y) are the coordinates of the mid-point of a line whose end

points are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then

$x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ Point C is the center of a circle

∵ AB is the diameter of the circle

∴ C is the mid point of AB

∵ A = (2 , 6) ⇒ $(x_{1},y_{1})$

∵ B = $(x_{2},y_{2})$

∵ C = (-1 , 2) ⇒ (x , y)

- Use the rule of the mid-point above

∵ $-1=\frac{2+x_{2}}{2}$

- Multiply both sides by 2

∴ -2 = 2 + $x_{2}$

- Subtract 2 from both sides

∴ $x_{2}$ = -4

∴ The x-coordinate of point B is -4

∵ $2=\frac{6+y_{2}}{2}$

- Multiply both sides by 2

∴ 4 = 6 + $y_{2}$

- Subtract 6 from both sides

∴ $y_{2}$ = -2

∴ The y-coordinate of point B is -2

The coordinates of point B are (-4 , -2)

Learn more:

You can learn more about the circle in brainly.com/question/9510228

#LearnwithBrainly

7 0

3 years ago

Determine the length of a chord whose central angle is 150° in a circle with a radius of 223 centimeters. Question 12 options: 1

faltersainse [42]

Answer:

4) 430.8 centimiters

Step-by-step explanation:

3 0

3 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0

3 years ago

Find the area of the shaded region in square units. Show your reasoning.

motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side $l$ , so, the area unit is $l^2$

the diagonal's square is $l\sqrt{2}$

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

$A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2$

CALCULATION OF MAIN SQUARE AREA

$A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2$

TOTAL AREA

$A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2$

3 0

3 years ago

If you pull eight coins from your pocket, and none of them are pennies, what is the most money that you could have? The least?

kramer

If you're based in the UK, you could say up to £800 as we have £100 coins here.

Lowest amount? Besides our penny our least valuable coin is the 2 penny coin. So barring pennies the least you could pull out of your pocket if you're based in the UK is 16p.

5 0

3 years ago

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