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pentagon [3]
3 years ago
8

A set of values is shown below.

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0
The answer is H- 4.9
AleksandrR [38]3 years ago
7 0

Answer:

the answer is f0

Step-by-step explanation:

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Answer below........
olganol [36]

ans: 70 ...( it is by ; 180-110) because of straight angle= 180...........

5 0
3 years ago
Need a answer to this please
ASHA 777 [7]
6 to the power of three is 216.
8 0
4 years ago
Read 2 more answers
The sketch shows two parallel lines cut by a transversal. Angle 1 is 58°. What is the measure of angle 7?
hodyreva [135]
The complete question in the attached figure

we have that
m∠1=<span>58°
</span>m∠7=?
 we know that
m∠1+m∠3=180°------------> supplementary angles
and 
m∠3=m∠7--------------------> corresponding angles
then
m∠3=180°-m∠1-----------> m∠3=180°-58°=122°

m∠7=m∠3=122°

the answer is m∠7=122°


3 0
3 years ago
Read 2 more answers
Solve by elimination:
neonofarm [45]

Answer:

x=−8

y=6=

Step-by-step explanation:

3x+4y=0

5x−3y=−58

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

3x+4y=0,5x−3y=−58

To make 3x and 5x equal, multiply all terms on each side of the first equation by 5 and all terms on each side of the second by 3.

5×3x+5×4y=0,3×5x+3(−3)y=3(−58)

Simplify.

15x+20y=0,15x−9y=−174

Subtract 15x−9y=−174 from 15x+20y=0 by subtracting like terms on each side of the equal sign.

15x−15x+20y+9y=174

Add 15x to −15x. Terms 15x and −15x cancel out, leaving an equation with only one variable that can be solved.

20y+9y=174

Add 20y to 9y.

29y=174

Divide both sides by 29.

y=6

Substitute 6 for y in 5x−3y=−58. Because the resulting equation contains only one variable, you can solve for x directly.

5x−3×6=−58

Multiply −3 times 6.

5x−18=−58

Add 18 to both sides of the equation.

5x=−40

Divide both sides by 5.

x=−8

The system is now solved.

x=−8,y=6

Coordinates are: (-8,6)

Graph:

7 0
3 years ago
What is the x-coordinate for the minimum point in the function f(x) = 4 cos(2x − π) from x = 0 to x = π?
melamori03 [73]
When you are looking at a graph, a minimum point would be where the curve is decreasing, then begins to increase. Right at the point where it switches, the slope is a horizontal line, or 0. We can take the derivative is f(x), then look for all the x values where the slope (which is equal to the first derivative) is equal to zero.

f'(x) = 2 * -4sin(2x - pi)

The 2 comes from the derivative of the inside, 2x-pi.

So now set the derivative equal to 0.

-8sin(2x-pi) = 0

We can drop the -8 by dividing both sides by -8.

sin(2x-pi) = 0

This can be rewritten as arcsin(0) = 2x-pi

So when theta equals 0, what is the value of sin(theta)? At an angle of 0, there is just a horizontal line pointing to the right on the unit circle with length of 1. Sine is y/h, but there is no y value so it is just 0. If arcsin(0) = 0, we can now set 2x-pi = 0

2x = pi

x = pi/2

This is a critical number. To find the minimum value between 0 and pi, we need to find the y values for the endpoints and the critical number.

f(0) = -4

f(pi/2) = 4

f(pi) = -4

So the minimum points are at x=0 and x=pi




5 0
4 years ago
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