9514 1404 393
Answer:
149.04°
Step-by-step explanation:
You must consider the signs of the components of the vector. The value -5+3i will be in the 2nd quadrant of the complex plane.
When you use the single-argument arctan function, it will tell you the angle is -30.96°, a 4th-quadrant angle. (arctan( ) is only capable of giving you 1st- or 4th-quadrant angles.)
You find the 2nd-quadrant angle by adding 180° to this value:
-30.96° +180° = 149.04° = arg(-5+3i)
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The attachments show the calculation using a suitable calculator (1st) and a spreadsheet (2nd). The spreadsheet function ATAN2(x,y) gives the 4-quadrant angle in radians, considering the signs of the two arguments. Here, we converted it to degrees. The calculator can be set to either degrees or radians.
The total area of the figure is the area of the square plus the area of the rectangle plus the area of the triangle.
area of the square: (6)*(6)=36cm^2
area of the rectangle: (7)*(6)=42cm^2
area of the triangle: (1/2)*(8)*(6)=24cm^2
total area
At=36+42+24=102cm^2
Yes because the median and range are not a function of the totality of the sample set, the median is just value that is halfway of the set. and the range are the difference of the highest and lowest value. as long as the lowest values, highest value and the halfway value are the same in each set the median and range will be equal no matter what are the other values of the set.
There’s not actually a question. But I might be able to help if u show the full problem
H = -2r + s/πr
C = 3A-a-b
If you need step by step comment
