y-y1 x-x1 -------- = ------- y2-y1 x2-x1
y-(-5) x-1 ------- = ---- 7-(-5) -3-1
y+5*(-4)=12*(x-1) -4y-20=12x-12 12x+4y+8=0 /4 3x+y+2=0
why: To form an linear equation for a line, you must remember 2 things
****First find its gradient, second, find the y-intercept.
General equation for a line: y = mx + c, where m = gradient, and c = y-intercept.
Gradient, m = {7 - (-5)} / {(-3) - 1} = - 3
To find the y-intercept, you must use one of the point (-3, 7) or (1, -5) and substitute the value of x and y from the coordinate u choose into the general equation y = mx + c.
I choose (1, -5), so -5 = -3(1) + c -5 = -3 + c -5 + 3 = c -2 = c
Thus,
the equation in slope-intercept form is y = -3x - 2.
the equation in standard form is y + 3x + 2 = 0
the equation in point-slope form is y + 3x = -2 divide both sides with -2 y / (-2) + 3x / (-2) = -2 / -2 - y / 2 - x / (2/3) = 1
Answer:
The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.
Step-by-step explanation:
The number of ways you can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.
Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.
This leads to the same value for the desired probability of a Yarborough:
32P13 / 52P13 = 0.000547.
Answer:
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Step-by-step explanation:
fsdvchrsdfg
Answer:
1+1= 11
1Step-by-step explanation:
I might be wrong so if i am right pls give me a thanks
