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Andru [333]
3 years ago
7

Solve the equation 1/4y+9=1/2

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

y = -34

Step-by-step explanation:

Step 1

1/4 y + 9 = 1/2

1/4 + 9 - 9 = 1/2 - 9

1/4 y = -17/2

Step 2

4 * (1/4 y) = 4* (-17/2)

y = -34

Hope this helps!!

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Solve 4x + 11 = k for x.
steposvetlana [31]

Answer:

Step-by-step explanation:

Simplifying

4x + 11 = k

Reorder the terms:

11 + 4x = k

Solving

11 + 4x = k

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.

11 + -11 + 4x = -11 + k

Combine like terms: 11 + -11 = 0

0 + 4x = -11 + k

4x = -11 + k

Divide each side by '4'.

x = -2.75 + 0.25k

Simplifying

x = -2.75 + 0.25k

4 0
3 years ago
Whats the answer please tell me
Nostrana [21]

Answer:

2 out of 10 or 2/10

Step-by-step explanation:

1 brown shoes + 7 black shoes = 8

that means there were 2 other students wearing neither so out of the 10 students 2 weren't wearing black or brown shoes making 2/10

7 0
3 years ago
Read 2 more answers
How much does Greg earn per hour? Explain how to determine the unit rate from the table?
Butoxors [25]

Answer:

Well you can already answer that(37)

Step-by-step explanation:

In 3 hours and 30 minutes Greg has earned 64.75 dollars if you take that amount(the amount earned in 3 and a half hours) and divide it by the 3 1/2 hours(the time it took to earn that amount) you get 18.50 which is the amount you earn per half hour since that graph is increasing at 30min. per 18.50 or the amount.

3 0
3 years ago
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
4 years ago
Find three consecutive odd integers so that the sum of twice the first, the second
netineya [11]

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

7 0
3 years ago
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