A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched
1 answer:
Answer:
104/4 pi
Step-by-step explanation:
Answer: The circumference of a circle is:
Radius = r, Diameter = d, C = Circumference
C=2πr (as 2r=d)
C=πd
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If the radius of the circle is 26" then its diameter must be 52".
This means that the bicycle wheel has a circumference of 52π".
I'm going to divide 52π" into 360 parts (because a circle is made up of 360 degrees). I'll then multiply this value by 80 to give you an answer.
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WX and ZY make up the legs, as illustrated in the diagram.
Since it is an isosceles trapezoid, the legs are congruent; that means
6<em>x</em> + 5 = 8<em>x</em> - 3
When solving this equation, we do not want a variable on both sides. We will cancel the 6<em>x</em> to avoid negatives:
6<em>x</em> + 5 - 6<em>x</em> = 8<em>x</em> - 3 - 6<em>x</em>
5 = 8<em>x</em> - 3 - 6<em>x</em>
Combine like terms:
5 = 2<em>x</em> - 3
Cancel the 3 by adding:
5 + 3 = 2<em /><em>x</em> - 3 + 3
8 = 2<em>x</em>
Cancel the 2 by dividing:
8/2 = 2<em>x</em>/2
4 = <em>x</em><em />
Since it is an isosceles trapezoid, the legs are congruent; that means
6<em>x</em> + 5 = 8<em>x</em> - 3
When solving this equation, we do not want a variable on both sides. We will cancel the 6<em>x</em> to avoid negatives:
6<em>x</em> + 5 - 6<em>x</em> = 8<em>x</em> - 3 - 6<em>x</em>
5 = 8<em>x</em> - 3 - 6<em>x</em>
Combine like terms:
5 = 2<em>x</em> - 3
Cancel the 3 by adding:
5 + 3 = 2<em /><em>x</em> - 3 + 3
8 = 2<em>x</em>
Cancel the 2 by dividing:
8/2 = 2<em>x</em>/2
4 = <em>x</em><em />