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Bess [88]
3 years ago
13

Solve this system of equations:

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0

y=2x so replacr the -y with -2x so 2x+6 is 8x. :)

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Answer:25 cm

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Diep bought a baguette loaf of bread 65 centimeters long. For lunch every afternoon, he cuts 15 centimeters of bread for his san
maxonik [38]
Given that the original length of the baguette is 65, and for each day 15 gets cut off, we have the function l(d) = 65 - 15d where d is a positive integer representing the nth day. As a matter of fact, the possible vaalues for d are 0, 1, 2, 3, and 4. Since on the 5th day, there won't be enough baguette anymore. This shows that the function l(d) is not continous since only certain points satisfy the condition. Thus, the function is l(d) = 65 - 15 where {d| 0 ≤ d ≤ 4} and it is discrete<span>.</span>
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djverab [1.8K]

Answer:

This approach to (0,0) also gives the value 0

Step-by-step explanation:

Probably, you are trying to decide whether this limit exists or not. If you approach through the parabola y=x², you get

\lim_{(x,y)\rightarrow (0,0)}\frac{xy}{\sqrt{x^2+y^2}}=\lim_{(x,x^2)\rightarrow (0,0)}\frac{xx^2}{\sqrt{x^2+(x^2)^2}}=\lim_{x\rightarrow 0}\frac{x^3}{|x|\sqrt{1+x^2}}=0

It does not matter if x>0 or x<0, the |x| on the denominator will cancel out with an x on the numerator, and you will get the term x²/(√(1+x²) which tends to 0.

If you want to prove that the limit doesn't exist, you have to approach through another curve and get a value different from zero.

However, in this case, the limit exists and its equal to zero. One way of doing this is to change to polar coordinates and doing a calculation similar to this one. Polar coordinates x=rcosФ, y=rsinФ work because the limit will only depend on r, no matter the approach curve.

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9 if your in k12 this is the answer trust me i just took the test
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