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a_sh-v [17]
3 years ago
13

- The part that is responsible for regulating involuntary processes in the body.

Biology
2 answers:
Ipatiy [6.2K]3 years ago
5 0

Answer:

Your medulla oblongata is located at the base of your brain, where the brain stem connects the brain to your spinal cord. It plays an essential role in passing messages between your spinal cord and brain. It's also essential for regulating your cardiovascular and respiratory systems.

I think its b ????. Sorry if it is wrong.

Explanation:

Mazyrski [523]3 years ago
3 0

Answer:

I am just in jss 2 but I think the ans is d

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Hellpp with this ill give brainliest
Ann [662]

Answer:the answer is A

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3 years ago
in a way everything we eat depends on photosynthesis describe how a breakfast of bacon and eggs depends on photosynthesis
Leokris [45]
Both chickens and pigs are omnivores so they eat scrap, grain, and most importantly for this subject vegetables and fruits. Vegetables and fruits both came from photosynthesis, so when we eat bacon and eggs we are eating pigs and chickens that ate plants and vegetables that gained energy due to photosynthesis. At least that’s what I think
4 0
3 years ago
The following F2 phenotypic data was obtained from a Drosophila testcross using an F1 offspring. Assume red eye and brown body a
dmitriy555 [2]

Answer:

The genotype of the F1 was wy+/w+y.

Explanation:

One of the given options has a typo: the red eye-brown body offspring count should be 56 instead of 561.

<u>We have two genes with two alleles each:</u>

Red eyes (w+) is dominant over white eyes (w).

Brown body (y+) is dominant over yellow body (y).

The phenotypes of the F2 tesulting from a test cross (F1 x wy/wy) are:

  • wy+/ey (white-eye, brown body): 670
  • w+y/wy (red-eye, yellow body): 650
  • wy/wy (white-eye, yellow body): 38
  • w+y+/wy (red-eye, brown body 56

If the genes w and y are linked, two phenotypes in the F2 will be much more abundant than the other two. Recombination during meiosis is a rare event, so the most abundant phenotypes are the parentals (the ones present in the F1 parent).

Every individual in the offpsring has a <em>wy</em> chromosome, as this was the gamete inherited from the test cross individual.

In this case, the most abundant gametes are wy+ and w+y, so the genotype of the F1 was wy+/w+y.

Notice how when recombination occurs in the F1 parent, the recombinant gametes appear: wy and w+y+, which are the less abundant in the F2 progeny.

8 0
3 years ago
If plants are absorbing and using blue and red light, what must be happening to other colours of light, like green and yellow?
Semenov [28]

Answer:

The colours like green and yellow are being reflected.

As we know if the colour is green then it is reflecting green light

Explanation:

8 0
3 years ago
Read 2 more answers
Assume that you have an illuminated suspension of Chlorella cells carrying out photosynthesis in the presence of 0.1% carbon dio
goldenfox [79]

Answer:

a. PGA down, RuBP up

Explanation:

RuBP, also known as Ribulose-1,5-bisphosphate is a molecule that assist in he fixation of carbon dioxide in the Calvin Cycle or light independent reaction of photosynthesis.

RuBP is combined with carbon dioxide using the enzyme known as rubisco to form an short-lived intermediate product which divides to form two 3-carbon molecule structure known as 3-phosphoglycerate.

<em>If the concentration of carbon dioxide is suddenly reduced, it thus means that the rate of production of 3-phosphoglycerate will reduce as carbon dioxide becomes a limiting factor. Hence, 3-phosphoglycerate's  concentration will reduce while more RuBP will become available as a result.</em>

The correct option is a.

3 0
3 years ago
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