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Dimas [21]
3 years ago
8

A candy store in the mall orders 1000 boxes a month each box of candy weighs 45.9 grams . What is the total weight in grams of t

he candy in the store
Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

45900 grams

Step-by-step explanation:

All you need to do is multiply 45.9 grams by 1000 for the total combined weight of every box combined to get.

45.9 x 1000 = 45900

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Add parentheses this equation true 2×2+12÷4+3=4
trasher [3.6K]

Answer:is this true or false or something?

Step-by-step explanation:

5 0
3 years ago
Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite
yarga [219]

Answer:

<em>Rajan must use </em><em>0.75</em><em> liters of 5% hydrochloric acid solution and </em><em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

x+y=1

i.e x=1-y --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

0.05x+0.45y=1\times 0.15

i.e 5x+45y=15 -------------2

Putting value of x from equation 1 in equation 2,

\Rightarrow 5(1-y)+45y=15

\Rightarrow 5-5y+45y=15

\Rightarrow 5+40y=15

\Rightarrow 40y=15-5=10

\Rightarrow y=0.25

Putting the value of y in equation 1,

x=1-0.25=0.75

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.

5 0
3 years ago
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
3 years ago
Can you please help me out on this​
Aloiza [94]

Answer:

B)

Step-by-step explanation:

because 45= 1(45)

the rest don't show it on the table

3 0
3 years ago
Read 2 more answers
An item costs $300 before tax, and the sales tax is $9.90 . Find the sales tax rate. Write your answer as a percentage.
Step2247 [10]

Answer:

3.33%

Step-by-step explanation:

9.90/300=0.033

8 0
2 years ago
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