Answer:
-3, 0, 5
Step-by-step explanation:
You want the zeros of P(x) = x³ − 2x² − 15x using the factored form.
<h3>Factored form</h3>
We notice right away that x is a factor of every term. Factoring that out gives us a quadratic to factor:
P(x) = x(x² -2x -15)
To factor this, we need two factors of -15 that have a sum of -2. The factors -5 and +3 have those properties. That means our factored form is ...
P(x) = x(x +3)(x -5) . . . . factored form
<h3>Zeros</h3>
This product will be zero when any of its factors is zero. Considering them one at a time, we find the zeros of P(x) to be ...
x = 0
x +3 = 0 ⇒ x = -3
x -5 = 0 ⇒ x = 5
The zeros of P(x) are -3, 0, 5.
Answer:
(, 3)
Step-by-step explanation:
Given the 2 equations
2x + 5y = 16 → (1)
10x - 3y = - 4 → (2)
Multiplying (1) by - 5 and adding to (2) will eliminate the term in x
- 10x - 25y = - 80 → (3)
Add (2) and (3) term by term
(10x - 10x) + (- 3y - 25y) = (- 4- 80) ← simplify
- 28y = - 84 ( divide both sides by - 28 )
y = 3
Substitute y = 3 into (1) or (2) for corresponding value of x
(1) : 2x + 15 = 16 ( subtract 15 from both sides )
2x = 1 ( divide both sides by 2 )
x =
Solution is (, 3 )
DE + EF = 4x+2
DE = x+7
EF = 7
Substitute these in
x + 7 + 7 = 4x + 2
x + 14 = 4x + 2
subtract x from both sides
14 = 3x + 2
subtract 2 from both sides
3x = 12
divide both sides by 3
x = 4
substitute this in to find the length of DE
DE = x + 7
(4) + 7 = 11
the answer is 11
Answer:
The answer is ""
Step-by-step explanation:
Let the given value is: