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adell [148]
3 years ago
13

What is the equation of the line that passes through the point (-6,-5) and has a slope of 2/3 ​

Mathematics
1 answer:
Leokris [45]3 years ago
3 0

Answer:

the answer is y=2/3x-5

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−3(y+5)=15 someone please help me with this question my assignment is already late
AnnyKZ [126]

Answer: -10

Step-by-step explanation:

Simplifying

-3(y + 5) = 15

Reorder the terms:

-3(5 + y) = 15

(5 * -3 + y * -3) = 15

(-15 + -3y) = 15

Solving

-15 + -3y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + -3y = 15 + 15

Combine like terms: -15 + 15 = 0

0 + -3y = 15 + 15

-3y = 15 + 15

Combine like terms: 15 + 15 = 30

-3y = 30

Divide each side by '-3'.

y = -10

Simplifying

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3 years ago
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Step-by-step explanation:

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Find AC and FB.<br> Points B, D, and F are midpoints of the sides of ACE. EC=40 and DF=18.
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