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miskamm [114]
3 years ago
6

Please help me with this

Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

(3,1) and (0,2)

Step-by-step explanation:

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The monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes). The mon
kkurt [141]

The monthly cost will be $17.14

Step-by-step explanation:

Given that the monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes) then this can be presented in a table form as;

<u>Time in minutes (x)</u>        <u>Cost in dollars (y)</u>

50                                          $12.55

102                                         $ 17.23

Take the values as ordered pairs to represent coordinates for points that satisfy the linear function

(50,12.55)  and (102,17.23)

Finding the slope of the graph using these points

slope,m=Δy/Δx

m=Δy=17.23-12.55 =4.68

Δx=102-50=52

m=4.68/52 =0.09

Finding the equation of the linear function using m=0.09, and point (50,12.55)

m=Δy/Δx

0.09=y-12.55/x-50

0.09(x-50)=y-12.55

0.09x-4.5=y-12.55

0.09x-4.5+12.55=y

y=0.09x+8.05

So for 101 minutes , the cost will be;

y=0.09*101 +8.05

y=9.09+8.05 = $17.14

Learn More

Linear functions : brainly.com/question/11052356

Keyword : linear function

#LearnwithBrainly

5 0
3 years ago
Write a problem that the expression 3(-7) -10 + 25 = -6
Sav [38]
This is true because the answer is -6 = -6
7 0
3 years ago
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Hi.
Keith_Richards [23]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Round 584,565 to the nearest hundred thousand.
lora16 [44]

Answer:

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Step-by-step explanation:

600,000

600,000

600,000

600,000

8 0
3 years ago
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Simplify this step by step<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-5jk%7D%7B35j%5E2k%5E2%7D%20" id="TexFormula1" tit
VikaD [51]
\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }

Remember that:

\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }
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