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3 years ago

Help me please and thank youu

Mathematics

2 answers:

gavmur [86]3 years ago

6 0

Answer:

-3

Step-by-step explanation:

faust18 [17]3 years ago

3 0

Answer:

-3

Step-by-step explanation:

y - y1 = m(x - x1) m = slope

y - 5 = -3(x - 17) slope = -3

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What is the expression in factored form? 9x^2-4 show all work

ziro4ka [17]

Answer:

$(3x+2)(3x-2)$

Step-by-step explanation:

we know that

A binomial is a Difference of Squares if both terms are perfect squares

we have

$9x^{2} -4$

$9x^{2}=(3x)^{2}$ ---> is a perfect square

$4=(2)^2$ ----> is a perfect square

Both terms are perfect squares

The difference of squares is

$9x^{2} -4=(3x+2)(3x-2)$ ----> by difference of squares

7 0

3 years ago

Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it use

evablogger [386]

Answer:

(1) Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$

Alternate Hypothesis, $H_1$ : $\mu_1\neq \mu_2$

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let $\mu_1$ = mean annual family income for 12 people making inquiries at the first development

$\mu_2$ = mean annual family income for 24 people making inquiries at the second development

$s_1$ = standard deviation of annual family income for 12 people making inquiries at the first development

$s_2$ = standard deviation of annual family income for 24 people making inquiries at the second development

$n_1$ = sample of people of first development i.e. 12

$n_2$ = sample of people of second development i.e. 24

(1) Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$ {population means are same}

Alternate Hypothesis, $H_1$ : $\mu_1\neq \mu_2$ {population means are different}

DECISION RULE ;

If the test statistics is less than the critical value of t from table at 5% significance level, then we will accept null hypothesis, $H_0$ .
If the test statistics is more than the critical value of t from table at 5% significance level, then we will reject null hypothesis, $H_0$ .

(2) The test statistics is given by;

$\frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1+n_2-2$

where, $X_1bar$ = Sample mean income of people at first development

= $153,000

$X_2bar$ = Sample mean income of people at second development = $171,000

$s_1$ = $42,000 and $s_2$ = $30,000

$s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2}}$ = $\sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2} }{12+24-2}}$ = 34344.30

Test statistics = $\frac{(153000 -171000) - 0}{34344.30\sqrt{\frac{1}{12}+\frac{1}{24} } }$ ~ $t_3_4$

= -1.48

(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

4 0

4 years ago

players on the school soccer team are selling candles to raise money for an upcoming trip. Each player has 24 candles to sell. I

kirza4 [7]

Step-by-step explanation:

Players on the school soccer team are selling candles to raise money for an upcoming trip. Each player has 24 candles to sell. If a player sells 4

hope this helps

8 0

4 years ago

Show that triangle BCD is isosceles

Sati [7]

∠A = 36
∠C =36
∠ADB =72°
∠CBD =36°
∠BDC =108°

Explanation:

AB=AD then ∠ABD & ∠ADB must be equal as they share two lines that are equal so ∠ADB=72°

∠A and ∠C must also be equal (AB=BC)
∠A = 180-72-72=36°
So ∠A & ∠C=36°

∠D=180° (straight line)
So if ∠ADC=72
∠BDC=108° (180-72)

A triangle has 180° so in triangle BDC we have 108° and 36°
So remaining angle (∠CBD) =180-108-36
=36°

This tells us that triangle BDC is isosceles as it has two equal angles ∠CBD & ∠C =36°

5 0

3 years ago

Read 2 more answers

Here is a question :3

lina2011 [118]

Answer:

D 41. 25

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers