N=32/3as a fraction alternative form is n=10.6
The missing length in the right triangle as given in the task content is; 156.
<h3>What is the missing length indicated?</h3>
It follows from the complete question that the triangle given is a right triangle and the missing length (longest side) can be evaluated by means of the Pythagoras theorem as follows;
x² = 144² + 60²
x² = 20736 + 3600
x² = 24,336
x = √24336
x = 156.
Remarks: The complete question involves a right triangle and the missing length is the longest side.
Read more on Pythagoras theorem;
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Answer:
![x=1\dfrac{4}{13}](https://tex.z-dn.net/?f=x%3D1%5Cdfrac%7B4%7D%7B13%7D)
Step-by-step explanation:
Given the equation
![10+5(3x-4)=2x+7](https://tex.z-dn.net/?f=10%2B5%283x-4%29%3D2x%2B7)
Use distributive property:
![10+5\cdot 3x-5\cdot 4=2x+7\\ \\10+15x-20=2x+7](https://tex.z-dn.net/?f=10%2B5%5Ccdot%203x-5%5Ccdot%204%3D2x%2B7%5C%5C%20%5C%5C10%2B15x-20%3D2x%2B7)
Use commutative property to rewrite the equation:
![15x+10-20=2x+7](https://tex.z-dn.net/?f=15x%2B10-20%3D2x%2B7)
![15x-10=2x+7](https://tex.z-dn.net/?f=15x-10%3D2x%2B7)
Add 10 th both sides:
![15x-10+10=2x+7+10\\ \\15x=2x+17](https://tex.z-dn.net/?f=15x-10%2B10%3D2x%2B7%2B10%5C%5C%20%5C%5C15x%3D2x%2B17)
Subtract ![2x:](https://tex.z-dn.net/?f=2x%3A)
![15x-2x=2x+17-2x\\ \\13x=17](https://tex.z-dn.net/?f=15x-2x%3D2x%2B17-2x%5C%5C%20%5C%5C13x%3D17)
Divide by 13:
![x=\dfrac{17}{13}=1\dfrac{4}{13}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B17%7D%7B13%7D%3D1%5Cdfrac%7B4%7D%7B13%7D)