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Kisachek [45]
3 years ago
5

Find the domain of 2y-b/y

Mathematics
1 answer:
vredina [299]3 years ago
4 0
(-∞,0) ∪ (0,∞) is your answer, for any other questions please ask!
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Which equation represents a proportional relationship?
ruslelena [56]
I believe it’s y=-3x+2
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3 years ago
Two numbers have an absolute value of 37. Which of the two number is farther from 1 on the number line
Brrunno [24]

If I understand what you're saying. It would be the absolute value of -37, which is 37. Also, the absolute value of 37 is 37.

3 0
3 years ago
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Help only 12 minutes left middle school math
Alex_Xolod [135]

Answer:

C?

Step-by-step explanation:

5 0
3 years ago
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A class of 40 students elected a class president. There were 12 votes for Candidate A, and 18 votes for Candidate B.
Helen [10]
Hey there, Bulgogi!

The correct answer will be the first one since [I'm assuming] you know that to calculate the percentage of something, it's the amount of that something divided by the total amount but since only 30 students voted [12+18] multiplied by 100.

So, we are calculating the percentage on votes and 12 students voted for Candidate A so our Numerator will be 12 and our Denominator will be the total amount of student who voted, so 30 [or 12+18]

Once put into a fraction, we will get \frac{12}{12+18} which would be equals to 2/5 or 0.4. Now we multiply by 100 and we get a total of 40% for Candidate A.

Thank you for using Brainly.
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4 0
4 years ago
A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3
Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = nPk=\frac{n!}{(n-k)!}

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts =  5P4+4P2+8P3

=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468

So, this can be done in 468 ways.

7 0
3 years ago
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