<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,
0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
The answer to your question is y = -1/4x + 15/4
Step-by-step explanation:
Data
P (-1, 4)
⊥ y = 4x + 1
Process
1.- Find the slope of the line given
y = 4x + 1
slope = 4
2.- Find the slope of the new line
slope 2 = -1/4
3.- Find the equation of the line
y - y1 = m(x - x1)
Substitution
y - 4 = -1/4(x + 1)
Simplification
y - 4 = -1/4x - 1/4
y = -1/4x - 1/4 + 4
y = -1/4x - 1/4 + 16/4
Result
y = -1/4x + 15/4
The smallest 3 common multiples of 2 and 3 are 6, 12, and 18 .
The smallest 3 common multiples of 3 and 6 are also 6, 12, and 18 .
Answer:
Step-by-step explanation:
Total number of marbles = 5 + 2 + 3 = 10
Probability of choosing 1 green marble = 2/10
Probability of choosing 1 yellow marble = 3/10
Notice (and this is important) that the denominator didn't change. Why?
Because you replaced the first marble into the bag. That word replacement is critical in a problem of this nature. There is the term non replacement which means that the second draw would have a denominator of 9.
So what is the probability of P(green then yellow)?
P(green then yellow) = 3/10 * 2/10 = 6/100
Answer: P(green then yellow) = 3/50 because 6 / 100 reduces.
