Answer:
Pair 1: 10 cm and 2 cm. and the sum is 12 cm.
Pair 2: 20 cm and 4 cm. and the sum is 24 cm.
Step-by-step explanation:
Area of a rectangle is given by A = LW, where L is the length and W is the width of the rectangle.
Pair 1:
For the first rectangle W = 4 cm and A = 40 sq, cm
Then
cm.
For the second rectangle W = 4 cm and A = 8 sq, cm
Then
cm.
Therefore, the sum of two unknown lengths = 10 + 2 = 12 cm. (Answer)
Pair 2:
For the first rectangle W = 4 cm and A = 80 sq, cm
Then
cm.
For the second rectangle W = 4 cm and A = 16 sq, cm
Then
cm.
Therefore, the sum of two unknown lengths = 20 + 4 = 24 cm. (Answer)
Answer:
B. 2
Step-by-step explanation:
Based on the Midsegment of a trapezoid theorem:
GH = (BC + FE)/2
9x - 3 = (19 + (5x + 1))/2) (substitution)
9x - 3 = (20 + 5x)/2
Cross multiply
2(9x - 3) = 20 + 5x
18x - 6 = 20 + 5x
Collect like terms
18x - 5x = 20 + 6
13x = 26
Divide both sides by 13
x = 26/13
x = 2
Answer:
8.80
Step-by-step explanation:
(S. D.)^2=summation(x-mean)^2/(n-1)
S. D.=sqrt(388/5)
S. D.=8.80