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Aleksandr-060686 [28]
3 years ago
11

Tim walked 2/5 of a mile on Monday, 6/7 of a mile on Tuesday, and 2/3 of a mile on Wednesday. How far did he walk in all?

Mathematics
2 answers:
bonufazy [111]3 years ago
6 0

Answer:

2 1/2

Step-by-step explanation:

I took the test

Nady [450]3 years ago
4 0
2/5 + 6/7 + 2/3....lowest common denominator is 105

42/105 + 90/105 + 70/105 = 202/105 =1 97/105 or  1.92 miles
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For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =
enyata [817]
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
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8 0
3 years ago
Simplify the expression 2.5(10x+8)+3x
IceJOKER [234]
The answer is: 28x + 8
7 0
3 years ago
Read 2 more answers
Please give me the correct answer ​
Mashutka [201]

Answer:

1st one

Step-by-step explanation:

Because It is just like a right triangle.

Also, look at how the bird is formed, it looks like a right triangle.

Also, I know it's a right triangle because of the length given.

Hope this helped!  

4 0
3 years ago
Read 2 more answers
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
3 years ago
Nick's Printing Press promptly sold 5-cent pencils and 10-cent pens to the public. It sold 1000 writing utensils and took $74.50
galben [10]

Answer:

  • 490 pens
  • 510 pencils

Step-by-step explanation:

Let p represent the number of pens Nick sold. Then the revenue is ...

  0.10p +0.05(1000 -p) = 74.50

  0.05p = 24.50 . . . . . . eliminate parentheses, subtract 50

  p = 490 . . . . . . . . . . . . multiply by 20

The number of pencils sold is then ...

  pencils = 1000 -490 = 510

Nick's Printing Press sold 490 pens and 510 pencils.

4 0
3 years ago
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