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AleksandrR [38]
3 years ago
5

Can someone help me pls

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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If f(x)=3x-1 and g(x)=x+2,find (f-g)(x)
oksian1 [2.3K]

Answer:

\large\boxed{(f-g)(x)=2x-3}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\f(x)=3x-1,\ g(x)=x+2\\\\\text{substitute:}\\\\(f-g)(x)=(3x-1)-(x+2)\\\\=3x-1-x-2\qquad\text{combine like terms}\\\\=(3x-x)+(-1-2)\\\\=2x-3

7 0
4 years ago
Im so confused! Can someone help me? I need to find the value of the variable and the measures of the angles.....
nikdorinn [45]
Hello there! I can help you! So what we are looking for is the value of x. To find the value of x, we can write and solve an equation. Set it up like this:

4x + 28 = 180

This is because the sum of the angles for a triangle is 180°. We combine the like terms to get 4x and subtract 6 from 34 to get 28. First off, let's subtract 28 from both sides. 28 - 28 cancel out. 180 - 28 is 152. That simplifies into 4x = 152. Now, divide each side by 4 to isolate the x. 4x/4 cancels out. 152/4 is 38. There's a possible value of x. Let's plug the value in and see if it works. 38 * 2 is 76. 76 - 6 is 70. 38 + 34 is 72. 70 + 72 is 142 and 142 + 38 is 180. 180 = 180. There. x = 38. Here are the answers for the angle measurements:

(x + 34) = 72°
(2x - 6) = 70°
x° = 38°

4 0
4 years ago
7x-9x what is the answer
Oksanka [162]

Answer:

-2x

Step-by-step explanation:

The expression itself is -2x. We subtract the coefficients 7 and 9 to get -2.

7 0
3 years ago
Read 2 more answers
Which is the best measure of central tendency for the type of data below–the mean, the median, or the mode? explain. hours of sl
djverab [1.8K]
Mean, because the outliers are limited.

There will be nights when you get more sleep or less sleep than usual, but overall, they will not be far away from the rest of the data you're comparing. 
8 0
3 years ago
Read 2 more answers
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
4 years ago
Read 2 more answers
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