Answer:
45
Step-by-step explanation:
1,3,5,9,15,45
At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
For this case, we must find an expression equivalent to:
By definition of power properties we have:
Rewriting the previous expression we have:
The "-" are canceled and we take into account that:
So:
According to one of the properties of powers of the same base, we must put the same base and add the exponents:
Answer:
Option B
Answer:
167.7
Step-by-step explanation:
210cos(37)=167.7134571
just type it in a calculator
Answer:
Let the amounts be 2x and 3x.
Then 2x+3x=60
So, 5x=60
So, x=60/5=12
So, amounts are
2x=2*12=24
And 3x=3*12=36
Hope this helps you!
Step-by-step explanation:
