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inn [45]
3 years ago
12

25% discount for AED 4000

Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:

The 25% discount on AED 4000 will be: 1000 AED

Step-by-step explanation:

Given

  • The amount = 4000
  • Discount = 25%

In order to determine a 25% discount on the amount AED 4000, all we need means is to multiply 25/100 or (0.25) by 4000.

i.e

Discount amount = 25% of 4000

                             = 25/100 × 4000

                             = 0.25 × 4000

                             = 1000 AED

Thus, the 25% discount on AED 4000 will be: 1000 AED

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PLEASE HELP!!!!<br> WILL MARK BRAINLIEST!!!!!
BigorU [14]

Answer:

I believe 3

Step-by-step explanation:

8 0
2 years ago
Find the area of a triangle bounded by the y-axis, the line f(x)=9−4/7x, and the line perpendicular to f(x) that passes through
Setler79 [48]

<u>ANSWER:  </u>

The area of the triangle bounded by the y-axis is  \frac{7938}{4225} \sqrt{65} \text { unit }^{2}

<u>SOLUTION:</u>

Given, f(x)=9-\frac{-4}{7} x

Consider f(x) = y. Hence we get

f(x)=9-\frac{-4}{7} x --- eqn 1

y=9-\frac{4}{7} x

On rewriting the terms we get

4x + 7y – 63 = 0

As the triangle is bounded by two perpendicular lines, it is an right angle triangle with y-axis as hypotenuse.

Area of right angle triangle = \frac{1}{ab} where a, b are lengths of sides other than hypotenuse.

So, we need find length of f(x) and its perpendicular line.

First let us find perpendicular line equation.

Slope of f(x) = \frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-4}{7}

So, slope of perpendicular line = \frac{-1}{\text {slope of } f(x)}=\frac{7}{4}

Perpendicular line is passing through origin(0,0).So by using point slope formula,

y-y_{1}=m\left(x-x_{1}\right)

Where m is the slope and \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)

y-0=\frac{7}{4}(x-0)

y=\frac{7}{4} x --- eqn 2

4y = 7x

7x – 4y = 0  

now, let us find the vertices of triangle, one of them is origin, second one is point of intersection of y-axis and f(x)

for points on y-axis x will be zero, to get y value, put x =0 int f(x)

0 + 7y – 63 = 0

7y = 63

y = 9

Hence, the point of intersection is (0, 9)

Third vertex is point of intersection of f(x) and its perpendicular line.

So, solve (1) and (2)

\begin{array}{l}{9-\frac{4}{7} x=\frac{7}{4} x} \\\\ {9 \times 4-\frac{4 \times 4}{7} x=7 x} \\\\ {36 \times 7-16 x=7 \times 7 x} \\\\ {252-16 x=49 x} \\\\ {49 x+16 x=252} \\\\ {65 x=252} \\\\ {x=\frac{252}{65}}\end{array}

Put x value in (2)

\begin{array}{l}{y=\frac{7}{4} \times \frac{252}{65}} \\\\ {y=\frac{441}{65}}\end{array}

So, the point of intersection is \left(\frac{252}{65}, \frac{441}{65}\right)

Length of f(x) is distance between \left(\frac{252}{65}, \frac{441}{65}\right) and (0,9)

\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(9-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+0} \\ &=\frac{252}{65} \end{aligned}

Now, length of perpendicular of f(x) is distance between \left(\frac{252}{65}, \frac{441}{65}\right) \text { and }(0,0)

\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(0-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+\left(\frac{441}{65}\right)^{2}} \\ &=\frac{\sqrt{(12 \times 21)^{2}+(21 \times 21)^{2}}}{65} \\ &=\frac{63}{65} \sqrt{65} \end{aligned}

Now, area of right angle triangle = \frac{1}{2} \times \frac{252}{65} \times \frac{63}{65} \sqrt{65}

=\frac{7938}{4225} \sqrt{65} \text { unit }^{2}

Hence, the area of the triangle is \frac{7938}{4225} \sqrt{65} \text { unit }^{2}

8 0
3 years ago
Can I please get help with this I give thanks
gladu [14]
First one :
We divide it into two rectangles (the top one has dimensions 2in*4in)

The area of the top rectangle is 2*4=8 in^2

The second rectangle has dimensions 3*(5-3)=6 in^2
Hence the total area is 8+6=14 square inches

Second one :

We divide it into a rectangle (dimensions 11*17) and a triangle on the top.

The area of the rectangle is 11*17=187 m^2
The rectangle has dimensions 17 (base's length) and 23-11 (height) hence its area is 17*(23-11)/2=102 m^2

Hence the total area is 102+187=289 square meters

6 0
3 years ago
Read 2 more answers
Need help ASAP! Directions in picture ;)
GuDViN [60]
The supplement of < 72 has the same measure as < (4x + 8). Therefore, < (4x + 8) must equal 108°. We can establish the following equality statement to solve for x:

< (4x + 8) + < 72° = 180°

Combine like terms:
4x + 80 = 180°

Subtract 80 from both sides:

4x + 80° - 80° = 180° - 80°

4x = 100

Divide both sides by 4 to solve for x:

4x/4 = 100/4

x = 25

To verify whether the value of x is correct, substitute its value into the equality statement:

< (4x + 8)° + < 72° = 180°

< [4(25) + 8]° + < 72° = 180°

< (100 + 8)° + < 72° = 180°

< 108° + < 72° = 180°

180° = 180° (True statement. Therefore, the correct answer is x = 25).

Please mark my answers as the Brainliest if you find this helpful :)
6 0
2 years ago
4. Find the surface area. Help me please
pogonyaev

Step-by-step explanation:

2πrh+2πr²=surface area

2π(3)(6)+2π(3²)

36π+18π

54π

8 0
3 years ago
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