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inn [45]
2 years ago
12

25% discount for AED 4000

Mathematics
1 answer:
Lostsunrise [7]2 years ago
5 0

Answer:

The 25% discount on AED 4000 will be: 1000 AED

Step-by-step explanation:

Given

  • The amount = 4000
  • Discount = 25%

In order to determine a 25% discount on the amount AED 4000, all we need means is to multiply 25/100 or (0.25) by 4000.

i.e

Discount amount = 25% of 4000

                             = 25/100 × 4000

                             = 0.25 × 4000

                             = 1000 AED

Thus, the 25% discount on AED 4000 will be: 1000 AED

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Which additional fact is needed to prove
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all except the first

Step-by-step explanation:

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Let U= {1,2,3,4,5,6,7,8,9,10}, A={2,4,6,8} B={1,2,3,4}, C={5,6,9}
user100 [1]

Answer: 13. is c, 14. is yes and 15 is no

Step-by-step explanation: Try your best and you might succeed

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3 years ago
Can someone plz help me on dis
julia-pushkina [17]

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6cm squared

Step-by-step explanation:

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4 0
2 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
2 years ago
two coins and a number cube are tossed at the same time. what is the approximate possibility that the coins show different sides
Stolb23 [73]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span>The results are independent:
P(2 heads) = 1/4
P(roll a 4) = 1/6
</span><span>P(2 heads and a 4) = (1/4)(1/6) = 1/24</span>
6 0
3 years ago
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