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inn [45]
3 years ago
12

25% discount for AED 4000

Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:

The 25% discount on AED 4000 will be: 1000 AED

Step-by-step explanation:

Given

  • The amount = 4000
  • Discount = 25%

In order to determine a 25% discount on the amount AED 4000, all we need means is to multiply 25/100 or (0.25) by 4000.

i.e

Discount amount = 25% of 4000

                             = 25/100 × 4000

                             = 0.25 × 4000

                             = 1000 AED

Thus, the 25% discount on AED 4000 will be: 1000 AED

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jarptica [38.1K]

1 foot = 12 inches.

0.75 feet x 12 inches per foot = 9 inches per day.

1 day = 24 hours.

9 inches /  24 hours = 0.375 inches per hour ( 3/8 inch per hour)

Not sure if you need a decimal or fraction for an answer so I provided both.

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Please help me with my math homework
Hatshy [7]

Answer:

So basically the mean is the average number.

Step-by-step explanation:

add all of them then divide by 6 (aka how many fractions)

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LenaWriter [7]

Answer:

2159.74

Step-by-step explanation:

you times 456 by 4 then you times that answer by the 1742%

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inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
I need helpppp:( like im failing this class
Olin [163]

Answer:

dont even stress i gotchu

It's 50*, 46* and 84*.

Ratio of the second problem is 1:1 they both have a slope of 1 (which is probably why all three points are on the same line)

Step-by-step explanation:

Since we know that the straight/flat angle would equal 180* we will set the total of all those angles to 180*

We will add them up to find x. Once we find x we can find the value of each angle.

6x-10 + 4x + 6 + 7x  + 14 = 180

We will combine like terms and solve for x.

17x+10 = 180

17x = 170

x = 10.

Since we have x = 10, we will plug it into x of each angle to get the value of each angle.

6(10) -10 = 60-10 which equals 50*

4(10) + 6 = 40+6 which equals 46*

7(10) + 14 = 70 + 14 which equals 84*.

8 0
3 years ago
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