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Mathematics

1 answer:

Hoochie [10]3 years ago

7 0

It should C or either D

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Solve for a.<br><br> a+(−1.2)=−5.5

Oksanka [162]

It is a + (-1.2) = -5.5
= a - 1.2 = -5.5
= a = -5.5 + 1.2
= a = -4.3

In short, Your Answer would be -4.3

Hope this helps!

4 0

3 years ago

Read 2 more answers

I'm stuck, plsss help ASAPP!!! :))

Bogdan [553]

Answer:

15 units

Step-by-step explanation:

$d \: = \sqrt{(x2 - x1) ^{2} + (y2 - y1) ^{2} }$

d = 14.866

d = 15

7 0

3 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$