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3 years ago

Yung bought $4.60 worth of bubble gum. Each piece of gum cost $0.10. How many pieces of bubble gum did Yung buy?

Mathematics

2 answers:

stellarik [79]3 years ago

5 0

Answer:

46 pieces

Step-by-step explanation:

We get n (number of pieces) as follows

n = (4.6 $) / (0.1 $/piece) = 46 pieces

Readme [11.4K]3 years ago

4 0

Answer:

Yung bought 46 pieces of bubble gum for $4.6

Explanation:

We are given that each piece of gum cost $0.1 and that he spent $4.6 on gums

To get the number of gums he bought, we will simply use cross multiplication as follows:

1 piece .........................> 0.1

x pieces ......................> 4.6

Therefore:

$x = \frac{4.6*1}{0.1}= 46$ pieces of gum

Hope this helps :)

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4 years ago

Which symbol creates a true sentence when x = 6? 12 ÷ x + 2x ____12 ÷ (x + 2x)

Serjik [45]

Answer:

The symbol can be $\neq, >$

Step-by-step explanation:

Given : Expression $12\div x+2x\ ?\ 12\div (x+2x)$

To find : Which symbol creates a true sentence when x = 6?

Solution :

$12\div x+2x\ ?\ 12\div (x+2x)$

We put x=6 both side and get the result,

LHS, $L=12\div x+2x$

$L=12\div 6+2(6)$

$L=2+12$

$L=14$

RHS, $R=12\div (x+2x)$

$R=12\div (6+2(6))$

$R=12\div (6+12)$

$R=12\div 18$

$R=0.6$

So we can say that,

$14\neq 0.6$ or $14> 0.6$

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4 years ago

The physical plant at the main campus of a large state university receives daily requests to replace fluorescent lightbulbs. The

Nikolay [14]

Answer:

$P(62< X< 72)= P(X$

Step-by-step explanation:

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

Let X the random variable who represent the courtship time (minutes).

From the problem we have the mean and the standard deviation for the random variable X. $E(X)=62, Sd(X)=5$

So we can assume $\mu=62 , \sigma=5$

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

So we need values such that

$P(X$

$P(X>\mu +\sigma)=P(X >67)=0.16$

$P(X$

$P(X>\mu +2*\sigma)=P(X>72)=0.025$

$P(X$

$P(X>\mu +3*\sigma)=P(X>77)=0.0015$

For this case we want to find this probability:

$P(62 < X< 72)$

And we can find this probability on this way:

$P(62< X< 72)= P(X$

Since $P(X>72) =0.025$ by the complement rule we have that:

$P(X$

And $P(X$ because for this case 62 is the mean.

So then we have this:

$P(62< X< 72)= P(X$

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