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Varvara68 [4.7K]
3 years ago
8

How many solutions are there to the system of equations graphed below if the lines are parallel?

Mathematics
1 answer:
damaskus [11]3 years ago
3 0
Zero
C is the correct option.
Step-by-step explanation:
In the given graph, the given lines are parallel to each other and hence never intersect.
Now, we know that the intersection point (s) of two curves gives us the solution.
Here the lines are parallel to each other and hence do not intersect each other.
Thus, there would not be any intersection point.
Hence, the system of equations has no solution.
C is the correct option.

Hope this helps

MARK AS BRAINLY PLSSSD
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Nevaeh invested $660 in an account paying an interest rate of 3% compounded
iris [78.8K]

Answer:

19

Step-by-step explanation:

Rate 1: 3  

4

1

​  

%=3+1/4=

\,\,3.25\%\rightarrow 0.0325

3.25%→0.0325

\text{Rate 2: }3\tfrac{1}{8}\%=3+1/8=

Rate 2: 3  

8

1

​  

%=3+1/8=

\,\,3.125\%\rightarrow 0.03125

3.125%→0.03125

\text{Calculate Final Amount for Nevaeh}

Calculate Final Amount for Nevaeh

\overline{\phantom{\text{Calculate Final Amount for Nevaeh}}}

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\text{Compounded Continuously:}

Compounded Continuously:

A=Pe^{rt}

A=Pe  

rt

 

P=660\hspace{35px}r=0.0325\hspace{35px}t=14

P=660r=0.0325t=14

Given values

A=660e^{0.0325(14)}

A=660e  

0.0325(14)

 

Plug in

A=660e^{0.455}

A=660e  

0.455

 

Multiply

A=1040.2744

A=1040.2744

Use calculator (with e button)

\text{Calculate Final Amount for Jonathan}

Calculate Final Amount for Jonathan

\overline{\phantom{\text{Calculate Final Amount for Jonathan}}}

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\text{Compounded Monthly:}

Compounded Monthly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

 

Compound interest formula

P=660\hspace{35px}r=0.03125\hspace{35px}t=14\hspace{35px}n=12

P=660r=0.03125t=14n=12

Given values

A=660\left(1+\frac{0.03125}{12}\right)^{12(14)}

A=660(1+  

12

0.03125

​  

)  

12(14)

 

Plug in values

A=660(1.0026042)^{168}

A=660(1.0026042)  

168

 

Simplify

A=1021.6468

A=1021.6468

Use calculator

\text{How much more money Nevaeh has:}

How much more money Nevaeh has:

1040.2744-1021.6468

1040.2744−1021.6468

18.6276

18.6276

\$ 19

$19

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