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nataly862011 [7]
3 years ago
10

Select the correct answer from each drop-down menu

Mathematics
1 answer:
hram777 [196]3 years ago
6 0

Answer:

Step-by-step explanation:

uv =5

wv=6

wu = (5²+6²)½

wu = 7.8 approximate 8

perimeter = 6+5+8 = 19

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Sam takes part in a car race that has 20 laps. He completes 4 laps every 3 minutes. The number of laps Sam has left to drive aft
Nadya [2.5K]
If we rewrite this equation, it would look like this: y=- \frac{4}{3}x+20, which is the equation for a straight line with a slope of -4/3 and a y-intercept of 20.  The y-intercept exists when x = 0.  "x" represents the number of minutes he drives, "y" represents the number of laps he drives.  Slope is rise/run, or y/x, which gives us that he drives 4 laps in 3 minutes (the slope of our line).  The y-intercept, when x = 0, tells us that when he has driven 0 minutes, or hasn't driven at all yet, he still has 20 laps to go.  When y = 0, the x-intercept is  0=- \frac{4}{3}x+20, and -20=- \frac{4}{3} x.  Multiply both sides by 3 to get that -60 = -4x and that means that x is 15.  This means that from start to finish, it takes him 15 minutes to drive the 20 laps. 
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3 years ago
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It 1 i hope its right 

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3 years ago
AB is congruent to DE because segment DE was constructed so that DE = AB. BC is congruent to EF because segment EF was construct
Alex Ar [27]

DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

<h3>Congruent shape</h3>

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

DF² = DE² + EF²

Also, In right triangle ABC, using Pythagoras:

AC² = AB² + BC²

But DE = AB and EF = BC, hence:

AC² = DE² + EF²

AC² = DF²

Taking square root of both sides, hence:

AC = DF

Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

Find out more on Congruent shape at: brainly.com/question/11329400

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3 years ago
Fill in the book value at the end of year 1 under each depreciation method when residual value is $36,000 and useful life is 4 y
3241004551 [841]

Answer:

Depreciation method:

Straight-line

$335,250

Units-of-Output

Double-declining

$217,50

Using Straight Line method:

Book Value= $335,250

6 0
4 years ago
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