SQ = square root
329 = 20 * SQ (273+ t)
Do the inverse of everything on the left
Divide by 20
Square your answer (329/20)
and subtract 273 from it
((329/20)^2)-273 = t
the temperature according to my calculations was <span>-2.3975 degrees
The nearest degree, if my math is correct was -2 degrees.
I'm not sure how to graph the equation, or I can't graph it for you, rather. Try Desmos if you need to graph it.

Mark brainliest if I helped you</span>

8 0

3 years ago

Use the law of cosines to find the length of a

borishaifa [10]

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

$\frac{sin55}{175}=\frac{sin42}{a}$ and solving for a:

$a=\frac{175sin42}{sin55}$ so

a = 143.0

4 0

3 years ago

2) If it is 12° outside and the temperature is going to -7° drop 19º. What will the new temperature be?

shutvik [7]

Answer:

69 degrees

Step-by-step explanation:

yeah

3 0

2 years ago

If 3 is added to three quarters of a certain number ,the result is 30 .find the original number.

cluponka [151]

Answer:

X=36

Step-by-step explanation:

Let x be the unknown number

Three quarters of a number =3x/4

Three was added =3x/4 +3

Final

3x/4 + 3= 30

Multiply through with 4

3x+ 12=120

3x=120-12

3x=108

X=108/3

X=36

6 0

3 years ago