The sum of squares of numbers is: 13
Step-by-step explanation:
Let x and y be two numbers
Then,
Difference of the squares of the numbers will be:

Product will be:

Given identity is:

Given values are:
Difference of the squares of the numbers=
Product of numbers = xy = 6
Putting the values in the identity
![(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%285%29%5E2%2B%5B2%286%29%5D%5E2%5C%5C%3D25%2B%2812%29%5E2%5C%5C%3D25%2B144%5C%5C%3D169)
As we have to only find x^2+y^2
Taking square root on both sides

The sum of squares of numbers is: 13
Keywords: Identities
Learn more about identities at:
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The answer for this question is incenter
Answer:OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF
Step-by-step explanation:OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF
Answer:
If Z is a complex number:
Z = a + b*i
where a and b are real numbers, and i is an imaginary number.
Then "a" is the real part.
"b*i" is the imaginary part.
The conjugate of Z is:
Zc = a - b*i
So the sign of the imaginary part changes.
Then:
Sum:
Z + Zc = (a + bi) + (a - bi) = 2*a + 0 = 2*a
and remember that a is a real number, then 2*a is also a real numer.
The correct answer is "A real number".
Difference:
Z - Zc = (a + bi) - (a - bi) = 2b*i
and this is a pure imaginary number, so here the correct answer is: "a pure imaginary number"