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3 years ago

Please help meeeeeeeeeeeee

Mathematics

1 answer:

Rina8888 [55]3 years ago

6 0

Answer:Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}

={------,-3,-2,-1,0,1,2,3,..........}

Step-by-step explanation:

→Points marked on the X and Y axis on the Coordinate Plane=Integers only

→Point to be marked on the coordinate plane =(-0.5,2)

→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.

→You can mark , any terminating decimal on the number line, which is marked with integers only.

→Terminating decimals are those decimals having in the denominator of a fraction.

So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.

→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).

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Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?

vovangra [49]

Answer: x≤ -0.5

Step-by-step explanation: Graph the two lines or solve for x:

2x – 6 ≥ 6(x – 2) + 8

2x – 6 ≥ 6x – 12 + 8

2x – 6 ≥ 6x – 4

-4x ≥ 2

x ≤ -1/2 [Inequality is reversed when multiplying or dividing by a negative number]

The number line is anything less than or equal to - 1/2

Or one can plot each side of the inequality and note the interception point (x = -(1/2)).

4 0

3 years ago

Endpoint 1: (-1,2)<br> Midpoint: (9,-6)<br> Endpoint 2=

Vlad [161]

Answer:

(19 , -14)

Step-by-step explanation:

Find the distance in between each x & y for a coordinate.

Let: (x₁ , y₁) = (-1 , 2)

Let: (x₂ , y₂) = (9 , -6)

From x₁ ⇒ x₂: 9 - (-1) = 10

From y₁ ⇒ y₂: -6 - 2 = -8 = 8*

*Remember that distance cannot be negative, but for the sake of this question, we will leave it as -8.

The distance between the x points are in intervals of 10. The distance between the y points are in intervals of 8. Add 10 & subtract 8 to their respective numbers to get endpoint 2:

(9 (+ 10) , -6 (- 8)) = (19 , -14)

Endpoint 2 = (19 , -14)

7 0

3 years ago

F(x)= (x+1)³ find f(x)¹<br><br>answer plz

Basile [38]

Answer:

f(x)^-1= $\sqrt[3]{x}$ -1

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Step-by-step explanation:

7 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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3 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

7 0

3 years ago