Answer:
Explanation:
i) On a cold day, Capacity = (66 X 910 X 10∧-9) F
Charge, Q = (66 X 910 X 10∧-9) X 5050 = 0.30 Columb
Current, I= 5050/131013 = 0.039 Amp (where Resistance = 131013 ohms)
Time, t= 0.30/0.039 = 7.7 seconds
ii) On a humid day, Capacity = (77 X 910 X 10∧-9) F
Charge, Q = ( 77 X 910 X 10∧-9) X 5050 = 0.35 Columb
Current, I= 5050/6106 = 0.83 Amp ( where Resistance = 6106 ohms)
Time, t= 0.35/0.83 = 0.42 h or 0.42 X 60 mins = 25 mins
Addresses packets at the internet layer
Answer:
int main() {
int _2dArray[32][32];
for (int i = 0; i < 32; i++) {
for (int j = 0; j < 32; j++) {
_2dArray[i][j] = j + i * 32;
}
}
return 0;
}
Explanation:
Here is a generic C/C++ 2d array traversal and main function example. The rest you'll have to figure out based on what kind of app you're making.
Good luck!
