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2 years ago

Factor the equation 25n^2+4

Mathematics

1 answer:

harkovskaia [24]2 years ago

7 0

Question: Factor 25 $n^{2}$ +4

25 $n^{2}$ +4 =

Doesn't factor

Answer:

25 $n^{2} \\$ +4

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Solve the inequality -6p<12 Ah this is due by tomorrow

777dan777 [17]

-6p < 12 Divide -6 on both sides to get "p" by itself

$\frac{-6p}{-6} < \frac{12}{-6}$

p > -2

When you divide or multiply a negative number to both sides of the inequality, the sign (< , > , ≤ , ≥) is flipped.

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3 years ago

Find m. DCR if m. RCB= 115° and m_ DCB = 169º.

Burka [1]

It is 54. Draw it out. You will see that DCB - RCB = DCR

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2 years ago

PLZ HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!During a 4-month-long drought, the water level in a lake changed

Dafna1 [17]

Answer:

-78

Step-by-step explanation:

4 Months is -312 so dividing by 4 will give the decrease of one month:

-312 ÷ 4 = -78

3 0

2 years ago

find the value of each variable in the circle to the right. the dot represents the center of the circle.

gladu [14]

We have been given an image of a circle. We are asked to find the value of each variable.

We can see that angle b corresponds to diameter of circle. We know that the measure of an angle that is inscribed to the diameter of a circle is 90 degrees . Therefore, the value of b will be 90.

we can see that angle is an inscribed angle of arc 99 degrees. We know that measure of an inscribed angle is half the measure of inscribed arc.

$a=\frac{1}{2}\cdot 99$

$a=49.5$

Therefore, the value of a is 49.5 units.

We know that measure of all angles of a triangle is 180 degrees. The measure of 3rd angle will be half the measure of c, so we can set an equation as:

$a+b+\frac{1}{2}c=180$

$49.5+90+\frac{1}{2}c=180$

$139.5+\frac{1}{2}c=180$

$139.5-139.5+\frac{1}{2}c=180-139.5$

$\frac{1}{2}c=40.5$

$\frac{1}{2}c\cdot 2=40.5\cdot 2$

$c=81$

Therefore, the value of c is 81.

3 0

2 years ago

Prove this trigonometric equation; - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

2 years ago