Answer:
B. 330
Step-by-step explanation:
got it right on edge :)
Let

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

So, the base case is ok. Now, we need to assume
and prove
.
states that

Since we're assuming
, we can substitute the sum of the first n terms with their expression:

Which terminates the proof, since we showed that

as required
Answer:
(64-23)8.3
Step-by-step explanation:
Solve the parenthesis first, then multiply
hope this helps! :)
Answer:
Claim is false
Step-by-step explanation:
Claim : A credit reporting agency claims that the mean credit card debt in a town is greater than $3500.

n = 20
Since n <30
So we will use t test
Formula : 
s = standard deviation = 391
x = 3600
n = 20


Degree of freedom = n-1 = 20-1 = 19
α=0.10
So, using t table
= 1.72
t critical > t calculated
So we accept the null hypothesis
Hence we reject the claim that the mean credit card debt in a town is greater than $3500.
Answer:
1/16
Step-by-step explanation:
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Hope This Helps :)</em></h2><h2><em>
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