Please use the symbol " ^ " to denote exponentiation: 9x^6 = (___)^2.
Note that 9x^6 = 3^2*(x^3)^2. Thus,
9x^6 = (___)^2 becomes (3x^3)^2.
Then <span>9x^6 – 16y^6 = (3x^3)^2 - (4y^3)^2 = ((3x^3) - (4y^3))[(3x^3) +(4y^3)]</span>
put it into an equation..
15+5v
sum is addition and product is multiplication
Answer:
1 4/6
Step-by-step explanation:
Measurement is the numerical quantitation of the attributes of an object or event, which can be used to compare with other objects or events. The scope and application of measurement are dependent on the context and discipline
Answer:
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Step-by-step explanation:
we know that
The <u><em>Power of a Power Property</em></u>
, states that :To find a power of a power, multiply the exponents
so

In this problem we have
![9^{\frac{1}{3}} =\sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B9%7D)
Remember that
![\sqrt[3]{9}=9^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Raise to the third power
![[9^{\frac{1}{3}}]^3](https://tex.z-dn.net/?f=%5B9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5D%5E3)
Applying the power of power property



therefore
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine