Answer:
Step-by-step explanation:
The absolute change in game length is ...
(180 min) -(150 min) = 30 min . . . . change in game length
__
The relative change is expressed as a fraction of the original game length:
(30 min)/(150 min) × 100% = 20% . . . . relative change in game length
Answer: 408.2 ft^2
Step-by-step explanation:
A=2πrh+2πr2
A=2(3.14)(5)(8)+2(3.14)(5)^2
A=6.28*40+6.28*25
A=251.2+157
A=408.2 ft^2
| shade | | | Each rectangle stands for one third so shade
| this | | | only one rectangle.
| one | | | And one rectangle has two books in it (you
| | | | divide 6 by 3 to get 2).
| | | |
| | | |
| | | |
Step-by-step explanation:
<u>Given</u>
- x + 2y = 3 and xy = 2
- show that x³ + 8y³ + 9 = 0
<u>Solution in steps:</u>
- (x + 2y)³ = 3³
- x³ + 3x²(2y) + 3x(2y)² + (2y)³ = 27
- x³ + 6x(xy) + 12y(xy) + 8y³ = 27
- x³ + 8y³ + 6(x + 2y)xy = 27 ⇒ Substitute values
- x³ + 8y³ + 6*3*2 = 27
- x³ + 8y³ + 36 - 27 = 0
- x³ + 8y³ + 9 = 0
Done
For problems like this, change the wording into simple algebraic
formulas. We know that the area of a rectangle is its width times its
length, or A=LW. The problem tells you that the area is 48, so LW=48.
Also, if the length = twice the width minus 4, then L=2W-4.
From here, substitute your new L value for the L in the first equation:
48=LW --> 48=(2W-4)W
Now solve this equation by factoring it out into a polynomial:
48=2W^2-4W --> 24=W^2-2W --> W^2-2W-24=0 --> (W+4)(W-6)=0.
Solving this equation gives us W values of 6 and -4, but since the width
of a rectangle cannot be negative, the width must be 6.
Since L=2W-4, then L=2(6)-4 --> L=12-4 = 8. Therefore, the dimensions are 6X8, or 6 feet by 8 feet.
To check our work: The length equals four feet less than twice the width: 8=2(6)-4 --> 8=12-4 --> 8=8. This checks out.
Also, the area is 48 ft^2, and (6)(8) = 48, so this also checks out.
Hopefully this helps. If you need any more help or if I went over something too quickly, just let me know.
