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likoan [24]
3 years ago
6

The sum of 15 and the product of five and V

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0

put it into an equation..

15+5v

sum is addition and product is multiplication

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NEED ANSWER ASAP!!! (EASY)
Nata [24]
3000(0.25)=750

C is correct. Hope this helps!
4 0
3 years ago
Read 2 more answers
The mean of five numbers is 6 the median is 7 and the mode is 2. What is the answer?
Lady_Fox [76]

Answer:

2,2,7,9,10

mark as brainliest

8 0
3 years ago
Match the number with its opposite. Match Term Definition 9.2 A) 2.9 −2.9 B) −4.1 −1.4 C) −9.2 4.1 D) 1.4
jenyasd209 [6]

We have these opposite pairs

  • 9.2 and -9.2
  • 2.9 and -2.9
  • 1.4 and -1.4
  • 4.1 and -4.1

So all we're doing is matching each positive number with its negative version. In terms of a visual, the opposite of a number is mirrored over 0 on the number line. So for instance, the opposite of 2 is -2, with each being two units away from 0 on the number line.

8 0
3 years ago
2. El perimetro de un rectangulo es 64 pies. Su largo es 12 pies mas que 3 veces su ancho. Halla las dimensiones del rectangulo
Afina-wow [57]
Ancho= x
Largo= 3x+12 ("12 pies más (adición) que 3 veces (multiplicación) su ancho (x)")

<span>En el problema incluyen el perímetro (la suma de todos los lados de una figura). </span>En un rectángulo, los lados opuestos son congruentes, así que para calcular el valor de x, tenemos que sumar nuestras ecuaciones.

(3x+12)+(3x+12)+x+x=64
8x=64-24
x=40/8
x=5

Luego lo único que queda hacer es substituir el valor de x en cada ecuación para calcular los valores que te piden.



4 0
3 years ago
The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil
satela [25.4K]

The length of pencil A is 5 cm

<em><u>Solution:</u></em>

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

<em><u>The total length of pencils A, B and C is 29 cm</u></em>

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

<em><u>Pencil A is 11 cm shorter then pencil B</u></em>

x = y - 11 ------- eqn 2

<em><u>Pencil B is twice as long a pencil C</u></em>

y = 2z

z = \frac{y}{2} ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16

<em><u>Substitute y = 16 in eqn 2</u></em>

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0
3 years ago
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