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gregori [183]
3 years ago
7

Solveee pleaseee with workkk

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

3 x 3 x 3 x 3 x 3 x 3 x 3 = 2,187

(or 3 x 7 = 2,187)

2,187 x 9 = 19,683

Step-by-step explanation:

The little seven next to the three is a exponent, that means there is the amount of threes as the exponent. Find out what 3 x 7 is. You should have gotten 2,187. Then multiply that answer that you got with the number you are multiplying with (9). You should get your answer 19,683.

Hope this helped you understand :)

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The area of a circle with the radius 3 feet is ____ ft^2 ? Rounded to the nearest hundredths
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28.26ft^2

Step-by-step explanation:

The formula for area of circle is:

A=3,14*r^2, where r =3 and 3,14 is pie number, so we have

A=3.14*9=28,26

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5

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10 / 2 = 5

5 times smaller also means 1/5 as big.

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What is the area in square feet of a triangle with a height of 4.5 and base of 6.6
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14.85

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What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

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