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const2013 [10]
3 years ago
12

Math mystery case of the alien apocalypse answers

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0
Well.. where’s the questions??
pishuonlain [190]3 years ago
5 0

Answer:??? i actually dont know what you are asking here.

Step-by-step explanation:

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Hi can someone help me out with this problem.
elena-s [515]

Answer:

third side = 9

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let the third side be x, then

x² + 40² = 41², that is

x² + 1600 = 1681 ( subtract 1600 from both sides )

x² = 81 ( take the square root of both sides )

x = \sqrt{81} = 9

The third side is 9

3 0
3 years ago
Read 2 more answers
Simplify -3[(-7)2 – 16] + 4 ÷ 2
katrin2010 [14]

Answer:

92

Step-by-step explanation:

3 0
3 years ago
Find the circumference of the circle iready area and circumference of a circle level g quiz
nekit [7.7K]

Answer:

Formula for circumference of a circle;

C = 2πr

To find the radius, we must find half(1/2) of the diameter.

Since we are given 6, we would find 1/2 of 6 which is <u>3</u>.

Now let's plug in these values into the formula:

C = 2πr

C = 2 x 3.14 x 3

C = 18.84 feet

5 0
3 years ago
Renata abrió su alcancía y le dijo a Raúl: “Tú tienes muy poco dinero ahorrado, la diferencia entre mi dinero y el tuyo es de $
rusak2 [61]
Jfjcjdjd tjxjcnccjfkfjff ;)
3 0
3 years ago
Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.
Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have points (1,6) and (2,2)

Slope is:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11

The equation of line will be:

y=mx+b\\y=-2x+11

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1

The equation of line will be:

y=mx+b\\y=\frac{1}{2}x+1

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

6 0
3 years ago
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