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3 years ago

Which expression is equivalent to (^5sqrt3^2)^1/3

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

6 0

Answer:

3^2/15

Step-by-step explanation:

(^5sqrt3^2)^1/3

(3^2/5)^1/3

multiply the powers

3^2/5*1/3

3^2/15

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Moving at its top speed a sloth would take 20 hours to go 3 miles on land. What’s that in miles per hour

olchik [2.2K]

Answer:

.15 mph

Step-by-step explanation:

3 miles/ 20 hours or 3/20

6 0

3 years ago

Read 2 more answers

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

3 years ago

Please answer all

vladimir1956 [14]

Step-by-step explanation:

b) y=x+1

table:

_x _|_2x_|_y_|(x, y)|

0 |2(0) |1 |(0, 1)|

1 | 2(1) |2 |(1, 2)|

2 | 2(2) |3 |(2, 3)|

3 | 2(3) |4 |(3, 4)|

c) y=3x+2

_x _|_2x_|_y_|(x, y)|

0 |2(0) |2 |(0, 2)|

1 | 2(1) |5 |(1, 5)|

2 | 2(2) |8 |(2, 8)|

3 | 2(3) |14 |(3, 14)|

To graph, plot the x, y points and connect all of them

7 0

3 years ago

If f(x) = 2x^2 - 5 and g(x) = 3x3, find (f-g)(x).

77julia77 [94]

$\text{Given that,}~ f(x) = 2x^2 -5 ~ \text{and}~ g(x) = 3x^3\\\\\text{Now,}\\\\ ~~(f-g)(x)\\\\=f(x) - g(x)\\\\=2x^2 -5 - 3x^3\\\\=-3x^3 +2x^2 -5$

4 0

2 years ago

Help please I really need

omeli [17]

Follow your directions then answer it it's easy

3 0

3 years ago