bearing in mind that an absolute value expression is in effect a piece-wise expression, because it has a ± version.
![\bf 3|x|+7=28\implies 3|x|=21\implies |x|=\cfrac{21}{3}\implies |x|=7\implies \begin{cases} +(x)=7\\ -(x)=7 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(x)=7\implies \boxed{x=7}~\hfill -x=7\implies \boxed{x=-7}](https://tex.z-dn.net/?f=%20%5Cbf%203%7Cx%7C%2B7%3D28%5Cimplies%203%7Cx%7C%3D21%5Cimplies%20%7Cx%7C%3D%5Ccfrac%7B21%7D%7B3%7D%5Cimplies%20%7Cx%7C%3D7%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%28x%29%3D7%5C%5C%20-%28x%29%3D7%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%2B%28x%29%3D7%5Cimplies%20%5Cboxed%7Bx%3D7%7D~%5Chfill%20%20-x%3D7%5Cimplies%20%5Cboxed%7Bx%3D-7%7D%20)
The answer is s = 2t - 1/2r
Answer:
(6x6x6x6) x (6x6x6)
Step-by-step explanation:
6 to the power of four is just 6 multiplied to itself 4 times.
6 to the power of three is just 6 multiplied to itself 3 times.
So, you would be multiplying 6, 7 times.
You could check it with a calculator. - 6^4 x 6^3 = 279936.
6^7 = 279936.
Hello there! The answer to your question is a = 4.
To solve for a in the equation -4 + 4a = 12 you want to isolate, or separate, a from all of the equation's other values.
Our first step is to add 4 to both sides so the 4 cancels out on the left side.
-4+4 + 4a = 12+4
4a = 16
Next, we divide both sides by 4 to finish isolating a.
4/4a = 16/4
a = 4
Want to verify that this is correct? Place the value we found for a (4) into the equation in place of a and if it comes out as a true statement, the answer is correct.
-4 + 4(4) = 12
-4 + 16 = 12
12 = 12
Since 12 is in fact equal to 12, i can guarantee you that i have provided you with the correct answer. I hope this helps & have a great rest of your day! :)
Answer:
<h2>88 cars</h2><h2>132 trucks</h2>
Step-by-step explanation:
This is a ratio problem, the ratio of cars to trucks
for every 4 cars, there are 6 trucks
represented as a ratio we have 4:6
1. how many of them are cars
applying the part to whole strategy we have
4+6 = 10
let cars be x
2. how many of them are trucks?
let trucks be y
