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likoan [24]
3 years ago
5

In order to compare functions we need to identify the

Mathematics
1 answer:
AysviL [449]3 years ago
3 0
X and y because they are the numerator and denominator
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A probability experiment will consist of selecting one student at random from your math class. Is the probability that the selec
kumpel [21]
Not likely because in my class we have more boys then girls 
m=27
f=5
8 0
3 years ago
Find the range.<br> 3-97-15-42
Anastaziya [24]

Well to find the range, you need to take the highest number and subtract the lowest from it:

3 - -97

3 + 97

100

Range is always positive

plz mark me as brainliest if this helped :)

3 0
3 years ago
Maria has a bag with 6 red marbles , 6 blue marbles , and 4 green marbles . Without looking Maria pick one marble. She does not
podryga [215]
40%

The probability of her getting a red marble is the number of red marbles divided by the number of total marbles. Since she picked a green marble first, we must subtract one marble from the total number of marbles, so that the total # of marbles is 6 + 6 + 4 = 16 - 1 (green marble) = 15. Since there are 6 red marbles, our probability is 6/15 or 2/5. Converted to percentage form, this is 0.4 —> 40%
7 0
3 years ago
How do you do this?PLZ HELP
Alisiya [41]
3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k

for this to be divisible by x every term must include x or get eliminated

the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3

so A) -3 is the solution
5 0
3 years ago
The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se
Rina8888 [55]

Answer:

<h2>3 and -8</h2>

Step-by-step explanation:

x,\ y-the\ numbers\\\\\text{The sum of four times a number and five times another number is -28:}\\\\4x+5y=-28\\\\\text{The sum of nine times the first number and two times the second number is 11:}\\\\9x+2y=11\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}4x+5y=-28&\text{multiply both sides by2}\\9x+2y=11&\text{multiply both sides by (-5)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}8x+10y=-56\\-45x-10y=-55\end{array}\right}\qquad\text{add both sides of the equation}

.\qquad-37x=-111\qquad\text{divide both sides by (-37)}\\.\qquad\qquad\boxed{x=3}\\\\\text{Put the value of x to the first equation:}\\\\4(3)+5y=-28\\12+5y=-28\qquad\text{subtrac 12 from both sides}\\5y=-40\qquad\text{divide both sides by 5}\\\boxed{y=-8}

3 0
3 years ago
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