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Lubov Fominskaja [6]
3 years ago
15

6) Read the article posted on The Verge entitled How to fight lies, tricks, and chaos online and summarize the four steps. Then

answer the following: Are these four steps enough guidance to help us discover truth in this day and age? Justify your answer with supporting arguments.​
Computers and Technology
1 answer:
netineya [11]3 years ago
3 0

Answer:

A. Summarily, the four steps to accurately sharing information include;

1. consciously employing our senses to examine news deeply so as to accurately determine their source and purpose.

2. determining the origin of the story so as to know when and where it stems from.

3. examining the context of the material so as to find inconsistencies.

4. analyzing the evidence, arguments and information being presented in the story.

B. The four steps presented in the story are enough guidance to help us differentiate between accurate and false information on the net.

I agree with all of the points presented by the author of this article on analyzing information found online. Recently, I viewed a video on the net which was presented as a fact but a little digging revealed that the original video was a prank that had been edited, so as to remove important details. The first point raised by the speaker which is honing my senses to know that something is wrong with the information (it was too bad to be true), helped me to dig deeper. I found a link to the original video that revealed a completely different detail from what I had just seen.

Explanation:

For people who care that the information they share online are true, the points raised by the author of the article, "How to fight lies, tricks, and chaos online", can prove beneficial. The first step is applying one's senses to know when an information is too bad or good to be true. The next step is determining the origin of the story. When and where a story comes from is crucial to knowing if it is truly relevant.

Thirdly, reading in between lines might reveal that the story is deceitful and lacks truth or originality. Lastly weighing the evidence of the story will help the reader in knowing the usefulness of the story to him.

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Calculate the time necessary to perform a multiply using the approach described in the text (31 adders stacked vertically) if an
Rudiy27

The time that will be used to perform a multiplication using the approach is 28 time units.

<h3>How to calculate time taken?</h3>

From the information given, the following can be noted:

A = 8 (bits wide)

B = 4 time units.

The multiplication will be performed based on the adder stack. Since A = 8, then, A - 1 = 8 - 1 = 7.

Now, the time taken will be:

= 7 × B

= 7 × 4tu

= 28 tu

In conclusion, the correct option is 28 time units.

Learn more about time taken on:

brainly.com/question/10428039

5 0
3 years ago
Given a following C program, where M and N are constant declared with #define long P[M][N]; long Q[N][M]; long sum_element(long
sladkih [1.3K]

Answer:

Check the explanation

Explanation:

The first, second and third instruction together set %rdx = 3*%rdi + %rsi. The fourth and fifth instruction set %rdi = %rdi+9*%rsi.

Now %rdi is used to address Q, while %rdx is used to address P. Note that P is addressed by column and then by row. Hence M = 3 . Also Q is addressed by row and then column, hence N = 9 .

3 0
4 years ago
1. Define class Elevator. For simplicity, we do not consider property like capacity (or weight limit), door (open or close), or
mihalych1998 [28]

Answer:

The source code is given below using Java

Explanation:

/*

* File: Passenger.java

*/

public class Passenger {

int currentFloor,targetFloor;//data members

//argumented constructor

public Passenger(int currentFloor, int targetFloor) {

this.currentFloor = currentFloor;

this.targetFloor = targetFloor;

}

//getter method

public int getCurrentFloor() {

return currentFloor;

}

//getter method

public int getTargetFloor() {

return targetFloor;

}

 

}

/***********************/

/*

File: Elevator.java

*/

public class Elevator {

int currentFloor, baseFloor, topFloor;//data members

public Elevator()//default constructor

{

baseFloor=1;

topFloor=6;

currentFloor=1;

}

//argumented constructor

public Elevator(int currentFloor, int baseFloor, int topFloor)

{ if(topFloor>=2 && baseFloor < topFloor && currentFloor>baseFloor && currentFloor < topFloor)

{

this.baseFloor=baseFloor;

this.topFloor=topFloor;

this.currentFloor=currentFloor;

}

else

{

baseFloor=1;

topFloor=6;

currentFloor=1;

}

}

// up method

public void up(int numFloors )

{

if(numFloors>0 && currentFloor+numFloors <=topFloor)

currentFloor+=numFloors;    

}

// down method

public void down(int numFloors )

{

if(numFloors>0 && currentFloor-numFloors >=baseFloor)

currentFloor-=numFloors;

}

//getter method

public int getCurrentFloor() {

return currentFloor;

}

//getter method

public int getBaseFloor() {

return baseFloor;

}

//getter method

public int getTopFloor() {

return topFloor;

}

 

}

/****************************/

/*

* File: PassengersTakeElevator.java

*/

import java.util.ArrayList;

public class PassengersTakeElevator {

//data members

Elevator elevator;

ArrayList <Passenger> passengers;

//default constructor

public PassengersTakeElevator() {

passengers=new ArrayList<>();

elevator=new Elevator();

Passenger p0=new Passenger(5, 2);

passengers.add(p0);

Passenger p1=new Passenger(3, 2);

passengers.add(p1);

Passenger p2=new Passenger(4, 3);

passengers.add(p2);

}

//argumented constructor

public PassengersTakeElevator(Elevator elevator, ArrayList<Passenger> passengers) {

this.elevator = elevator;

this.passengers = passengers;

}

//schedule method

public void schedule(){

for(int i=0;i<3;i++)

{

Passenger p=passengers.get(0);//gets passenger at head

 

System.out.println("Passenger "+i+" is at Fl "+p.getCurrentFloor()+", will go to Fl "+p.getTargetFloor());

System.out.println("Elevator is at Fl "+elevator.getCurrentFloor());

int numFloors=p.getCurrentFloor()-elevator.getCurrentFloor();

if(numFloors>0)

{

System.out.println("Elevator moves up from Fl "+elevator.getCurrentFloor()+" to Fl "+p.getCurrentFloor());

elevator.up(numFloors);

System.out.println("Elevator carries passenger down from Fl "+p.getCurrentFloor()+" to Fl "+p.getTargetFloor());

numFloors=p.getCurrentFloor()-p.getTargetFloor();

elevator.down(numFloors);

}

else if(numFloors<0)

{

System.out.println("Elevator moves down from Fl "+elevator.getCurrentFloor()+" to Fl "+p.getCurrentFloor());

elevator.down(-numFloors);

System.out.println("Elevator carries passenger up from Fl "+p.getCurrentFloor()+" to Fl "+p.getTargetFloor());

numFloors=p.getTargetFloor()-p.getCurrentFloor();

elevator.up(numFloors);

 

}

else

{ numFloors=p.getTargetFloor()-p.getCurrentFloor();

if(numFloors>0)

{

System.out.println("Elevator carries passenger up from Fl "+p.getCurrentFloor()+" to Fl "+p.getTargetFloor());

elevator.up(numFloors);

}

else

{

System.out.println("Elevator carries passenger down from Fl "+p.getCurrentFloor()+" to Fl "+p.getTargetFloor());

elevator.down(-numFloors);

}

}

passengers.remove(0);//removes passenger at head

}

}

}

/*****************************/

/*

* File: TestPassengersTakeElevator.java

*/

import java.util.ArrayList;

public class TestPassengersTakeElevator {

public static void main(String[] args) {

//object of PassengersTakeElevator

System.out.println("Schedule 1");

PassengersTakeElevator obj1=new PassengersTakeElevator();

obj1.schedule();//calling schedule method of PassengersTakeElevator

ArrayList <Passenger> passengers=new ArrayList<>();

Elevator elevator=new Elevator();

Passenger p0=new Passenger(1, 5);

passengers.add(p0);

Passenger p1=new Passenger(2, 4);

passengers.add(p1);

Passenger p2=new Passenger(4, 1);

passengers.add(p2);

System.out.println();

System.out.println("Schedule 2");

PassengersTakeElevator obj2=new PassengersTakeElevator(elevator,passengers);

obj2.schedule();//calling schedule method of PassengersTakeElevator

 

 

}

 

}

7 0
4 years ago
Create a named range called, "Savings" that references the cell that calculates the monthly savings in your budget. The savings
Katen [24]
Is this to be done in excel?
3 0
3 years ago
Read 2 more answers
Write a function findEvenQueue that returns the first even number in the Queue. The function looks at the value at the front of
Bumek [7]

Answer:

Check the explanation

Explanation:

CODE:

static int findEvenQueue(Queue<Integer> numbers)

{

//loop runs till the queue has atleast one element

while(numbers.size() > 0)

{

//Checking the head of the queue whether it is even

int temp = numbers.peek();

if(temp % 2 == 0)

{

//if the head is even then return it

return temp;

}

else

{

//else remove the number at head

int removed = numbers.poll();

}

}

//if no even number present in the Queue then return -1

return -1;

}

4 0
3 years ago
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