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Montano1993 [528]
3 years ago
7

Find the measures of

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0
X= 26 y=26

As 130+88=308
360-308=52
52/2=26
The two sides are equal so they would be both 26
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The graphs below have the same shape. What is the equation of the red<br> graph?
umka2103 [35]
The answer is D
g(x)= -x^2
5 0
3 years ago
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Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are rando
qwelly [4]

Answer: The probability that both televisions work is 0.5625 .

The probability at least one of the two televisions does not​ work is 0.4375.

Step-by-step explanation:

Given : Number of televisions received in shipment= 12

Number of defective televisions received in shipment= 3

Then proportion of defective televisions =\dfrac{3}{12}=0.25

Using binomial probability formula, the probability of getting success in x trials is given by :-

P(x)=^nC_xp^x(1-p)^{n-x}

If two televisions are randomly​ selected, then the probability that both televisions work will be :-

P(0)=^2C_0(0.25)^0(0.75)^2=(0.75)^2=0.5625

The probability at least one of the two televisions does not​ work will be :-

P(x\geq1)=1-P(0)=1-0.5625=0.4375

6 0
3 years ago
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
Domain of the function of a graph with coordinates (-3,-2)
olga2289 [7]

Answer:

Domain is -3

Step-by-step explanation:

Given that coordinate of a graph is (-3, -2)

We have to find out the domain.

We know that if A and B are two sets, a mapping from A to B is the subset of cartesian product AxB.

Domain is the set of values of A which have images in B.

Use the above definition.

We have A = {-3,...} and B = {-2,....}

The mapping is from -3 to -2

Hence domain is -3

6 0
3 years ago
What is the area of the triangle?
Arada [10]
The answer is 6 square inches
4 0
3 years ago
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