3 years ago

Three times the square of a certain positive number exceeds six times the number by nine. find the number:

1 answer:

4 0

With the number being x, we have 3x^2>6(x/9). Expanding, we get 3x^2>6x/9 and 3x^2>2x/3. Dividing by x, we get 3x>2/3 and dividing by 3 we get x>2/9

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It’s 4 because y is a variable plus any number in front of a variable makes it a coefficient

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horrorfan [7]

Answer: 80

Step-by-step explanation:

We can use the formula $A=\frac{d_{1}d_{2}}{2}$ , where $d_{1}, d_{2}$ are the lengths of the diagonals.

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$AC=\sqrt{(-2-2)^{2}+(-1-7)^{2}}=\sqrt{16+64}=4\sqrt{5}\\BD=\sqrt{(-8-8)^{2}+(-1-7)^{2}}=\sqrt{256+64}=8\sqrt{5}$

So, the area is $\frac{(4\sqrt{5})(8\sqrt{5})}{2}=\boxed{80}$

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Ierofanga [76]

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lakkis [162]

Answer:

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