Ok you need to do y-(-2) over -3-(-9) and you get(y+2)/(-3+9)=1
so y+2=1*6
y+2=6
y=4
Assuming you are referring to the area of a "trapezoid"; in which one calculates the Area, "A", as follows:
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<span> A = 1/2* h(b1+b2) ;
in which: A = Area = 16 (given);
h = height = 4 (given);
b1 = length of one of the two bases = 3 (given);
b2 = length of the other of the two bases = ? (what we want to solve for) ;
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Using the formula: </span>A = 1/2 h(b1+b2) ;
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Let us plug in our known values:
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→ 16 = (1/2) * 4*(3 + b2) ; → Solve for "b2".
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→Note: On the "right-hand side" on this equation: "(1/2)*(4) = 2 ."
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So, we can rewrite the equation as:
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→ 16 = 2*(3 + b2) ; → Solve for "b2".
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We can divide EACH side of the equation by "2"; to cancel the "2" on the "right-hand side" of the equation:
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→ 16 / 2 = [2*(3 + b2)] / 2 ; → to get:
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8 = (3 + b2) ;
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→ Rewrite as: 8 = 3 + b2;
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Subtract "3" from EACH side of the equation; to isolate "b2" on one side of the equation; and to solve for "b2" :
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→ 8 - 3 = 3 + b2 - 3 ; → to get:
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b2 = 5; From the 2 (TWO) answer choices given, this value,
"b2 = 5", corresponds with the following answer choice:
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b2= [16-6]/2= 5 ; as this is the only answer choice that has: "b2 = 5".
<span>_________________________________________
As far getting "</span>b2 = 5" from: "b2= [16-6]/2= 5"; (as mentioned in the answer choice), we need simply to approach the problem in a slightly different manner. Let us do so, as follows:
<span>_____________________________________
Start from: </span>A = 1/2 h(b1+b2); and substitute our known (given) values):<span>
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</span>→ 16 = (1/2) *4 (3 + b2) ; → Solve for "b2".
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Note that: (½)*4 = 2; so we can substitute "2" for: "(1/2) *4" ;
and rewrite the equation as follows:
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→ 16 = 2 (3 + b2) ;
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Note: The distributive property of multiplication:
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a*(b+c) = ab + ac ;
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As such: 2*(3 + b2) = (2*3 + 2*b2) = (6 + 2b2).
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So we can substitute: "(6 + 2b2)" in lieu of "[2*(3 + b2)]"; and can rewrite the equation:
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→ <span>16 = 6 + 2(b2) ; Now, we can subtract "6" from EACH side of the equation; to attempt to isolate "b2" on one side of the equation:</span>
<span>________________________________________________
</span>→ 16 - 6 = 6 + 2(b2) - 6 ;
→ Since "6-6 = 0"; the "6 - 6" on the "right-hand side" of the equation cancel.
→ We now have: 16 - 6 = 2*b2 ;
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Now divide EACH SIDE of the equation by "2"; to isolate "b2" on one side of the equation; and to solve for "b2":
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→ (16 - 6) / 2 = (2*b2) / 2 ;
→ (16 - 6) / 2 = b2 ;
→ (10) / 2 = b2 = 5.
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NOTE: The other answer choice given:
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"<span>16= 1/2* 4(3+b2)= 6+2b2" is incorrect; since it does not solve for "b2".</span>
8 apples and 4 bananas as 8x =£8.00 and 4y=£2.00 and 8+4=12 and £8+£4=£10
Answer:
The system is INCONSISTENT.
Equation of two parallel lines differ only by a constant.
Step-by-step explanation:
The given equations are:
2x + y = -11
6x + 3y = 15
From the graph we see that these lines are parallel. Any two parallel lines never meet. Hence, they do not have a solution.
Hence, the system is called an Inconsistent system.
Also, note that it can be seen easily from the equations are parallel without the help of a graph.
The equation 6x + 3y = 3(2x + y)
The terms (except for the constant term) are proportional. That means they represent parallel lines.
Hence, the answer.
He pushed them together to have the most surface area when he was done, so that tells us he put the two smallest sides together.
Essentially, he put them end to end to make a really long prism. The two sides pressed together are both 3x4 so
2(3x4) = 2(12) = 24
