It can be, but it depends on the last number. if its even the number is then even.
Step-by-step explanation:
log x = 1 + a
a = log x - 1
log y = 1 - a
a = 1 - log y
So
log x - 1 = 1 - log y
log x + log y = 2
log (xy) = 2
xy = 100
I think the correct answer is A. Hope this helps.
Center of the circle: C=(3,8)=(h,k)→h=3, k=8
Radius of the circle: r=5
Standard form of the equation for the circle:
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-8)^2=5^2
(x-3)^2+(y-8)^2=25
General for of the equation for the circle:
(x)^2-2(x)(3)+(3)^2+(y)^2-2(y)(8)+(8)^2=25
x^2-6x+9+y^2-16y+64=25
x^2+y^2-6x-16y+73=25
x^2+y^2-6x-16y+73-25=25-25
x^2+y^2-6x-16y+48=0
Answer: The general form of the equation for the circle is:
x^2+y^2-6x-16y+48=0
