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Ivenika [448]
3 years ago
14

I NEED HELP ASAP!!!! PLEASE HELP!!!

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

y= 2x-3  m=2 b= -3

Step-by-step explanation:

we distribute 2(x-2)

y-1 = 2(x-2)

y-1 = 2x-4

then add one to both sides

y-1= 2x -4

 +1       +1

since it is negative four and you are adding one it would be -3

y= 2x -3  that is your slope intercept form.

y= mx +b  so m=2 and b= -3

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HELP QUICK I NEED AN ANSWER RN PLS
amm1812

Answer:

r = 3.7 cm

Step-by-step explanation:

19.02 = 1/2π(2radius) + diameter

expanding:

19.02 = 1/2(3.14)(2r) + 2r

19.02 = 3.14r + 2r = 5.14r

r = 19.02/5.14 = 3.7 cm

4 0
3 years ago
If 400ml of milk is used for 8 pancakes then how much is used for 6
Naddik [55]

To solve this equation, you will need to set up a proportion where you set two fractions equal to each other.

Let x = the unknown amount of milk

\frac{400}{8} = \frac{x}{6}

You would then crossmultiply and solve for x.

8x = 400(6)

8x = 2400

x = 2400/8

x = 300

You will need 300 mL of milk to make 6 pancakes if you previously needed 400 mL to make 8 pancakes.

3 0
3 years ago
Ice cream sales (in gallons) fluctuate from month to month, depending on the season. A local ice cream lover would like to condu
Oksi-84 [34.3K]

This is two independent sample test.                                                                                                                        

<u>Step-by-step explanation</u>:

  • Ice cream sales will fluctuate from month to month. So sales will differ every month. A separate sale will be made on Blank Slate Creamery.
  • A first sample test will be taken on  Blank Slate Creamery. After that, the average value will be noted. Now sales will be noted on Ben & Jerry's. After that value will be added.
  • Now, these two values will be compared. We should check which has the highest value. Using this we can identify which ice cream has a higher record.      

                       

7 0
4 years ago
How do i solve this? what is the answer?
timurjin [86]

Answer:

solve what? the picture is not loading...

Step-by-step explanation:

I am so sorry I really want to help

7 0
4 years ago
According to a 2009 Reader's Digest article, people throw away approximately 11% of what they buy at the grocery store. Assume t
expeople1 [14]

Answer:

0.14% probability that the sample proportion exceeds 0.2

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 108, p = 0.11

So

\mu = E(X) = np = 108*0.11 = 11.88

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{108*0.11*0.89} = 3.2516

What is the probability that the sample proportion exceeds 0.2

This is 1 subtracted by the pvalue of Z when X = 0.2*108 = 21.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21.6 - 11.8}{3.2516}

Z = 2.99

Z = 2.99 has a pvalue of 0.9986

1 - 0.9986 = 0.0014

0.14% probability that the sample proportion exceeds 0.2

8 0
4 years ago
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