Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.
Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.
Any function f(d) to find excess of children more than adults can be written as follows :-
f(d) = c(d) - a(d).
⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)
⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9
⇒ f(d) = 0.1d² + d + 2
14 trout out of 50 total fish. The total amount of fish in the lake is 7500. Let’s make this into a proportion.
14/50=x/7500
x represents how much trout is in the lake, we don’t know yet, but we’ll find out.
First, cross multiply.
14*7500=105000
50*x=50x
Now let’s turn this into an equation.
50x=105000
Divide both sides by 50
50x/50=x
105000/50=2100
x=2100
Out of the 7500 fish in the lake, 2100 were trouts.
2/3!
I hope this helped! Mark me Brainliest! :) -Raven❤️
You can make a 6 x 6 square to illustrate the probabilities
1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 *
5 6 7 8 9 * &
6 7 8 9 * & $
* =10, & =11, $ = 12, I wanted maintain spacing
There are 3 4's. So it is 3/36 chance, which is 1/12 chance.
