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beks73 [17]
3 years ago
14

Each month, 8 magazines arrive at Sydney's home. Write an equation that would show the number of motnths (n) it took for Sydney

to receive 56 magazines.
btw this is multiple choice so this is the choices
A. 56n=8
B.n+8=56
C.8n=56
D.56-n=8
help me asap​
Mathematics
1 answer:
Dovator [93]3 years ago
7 0
C.
Since 8 magazines are areiving each month (n) and the total is 56, all you have to do is multiply 8 by n and you get 56, the actual answer would be 7 though.
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Scott has eight CDs, and he picks two to take to work each day. How many different ways can Scott choose two CDs?
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The total number of ways to select 2 CDs from 8 CDs is 28.

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Delta Airlines' flights from Boston to Seattle are on time 70 % of the time. Suppose 6 flights are randomly selected, and the nu
emmainna [20.7K]

Answer:

P(at least 4)  = 0.74431

Step-by-step explanation:

Here

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q= 0.3

n= 6

As the probability of success and failure is constant and the n is also fixed then the binomail probability distribution can be used to solve this.

P (x= 4) = 6c4 *(0.7)^4 (0.3)^2= 15*0.2401* 0.09= 0.324135

P (x= 5) = 6c5 *(0.7)^5(0.3)^1= 6*0.16807* 0.3=0.302526

P (x= 6) = 6c6 *(0.7)^6 (0.3)^0= 0.117649P

P (x= 0) = 6c0 *(0.7)^0 (0.3)^6= 0.000729

P (x= 1) = 6c1 *(0.7)^1 (0.3)^5=0.010206

P (x= 2) = 6c 2*(0.7)^2 (0.3)^4=0.059535

P (x= 3) = 6c3 *(0.7)^3 (0.3)^3=0.18522

Probability of at least 4 means that probability of greater than 4 inclusive of 4.

This can be obtained in two ways.

First is by subtracting the probabilities of less than 4.

Second is by adding probabilities greater than 4 including 4.

We get the same answer with any of the two methods used.

P(at least 4) = 1- P(x<4)

                     = 1- [ 0.000729+ 0.010206 +0.059535+ 0.18522]

                     = 1- 0.25569

                       = 0.74431

P (at least 4) = P(x=4) +P(X=5) + P(x=6)

                        =0.324135+ 0.302526+ 0.117649

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7 0
2 years ago
Match the distance with their respective endpoint coordinates
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(2,4) and origin
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(7,8) and (-2,20)
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Arranging the distances will give us an answer of C, D, A, B, E
The answer is letter C. 
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