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3 years ago

Can SOMEONE HELP ME PLEASEEEEE!!! PLEASE PLEASE PLEASE I NEED HELPPPP!!!!

Mathematics

1 answer:

Papessa [141]3 years ago

7 0

Answer:

7.95 * 2 + 5.00 + 10

Step-by-step explanation:

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What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 8y + 21=0

NeTakaya

Answer:

Step-by-step explanation:

(x²-6x)+(y²+8y)=-21

(x²-6x+9)+(y²+8y+16)=-21+9+16

(x-3)²+(y+4)²=4

center=(3,-4),radius=√4=2

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3 years ago

Write and solve an equation for:

geniusboy [140]

Answer:

n = - 12

Step-by-step explanation:

n + 6 = 2n/4

4 (n+6) = 2n

4n + 24 = 2n

4n - 2n = - 24

2n = -24

n = - 24/2

n = - 12

6 0

3 years ago

I need help completing this problem ASAP

prisoha [69]

Answer:

$4\sqrt{5}$

Step-by-step explanation:

Prime factorize 20 and 45

$\sqrt{20}=\sqrt{2*2*5}=2\sqrt{5}\\\\\\\sqrt{45}= \sqrt{5*3*3}=3\sqrt{5}$

$\sqrt{20}-\sqrt{5}+\sqrt{45}=2\sqrt{5}-\sqrt{5}+3\sqrt{5}$

$=(2-1+3)\sqrt{5}\\\\\\= 4\sqrt{5}\\$

4 0

3 years ago

-3 - 6(4x+6) = -11<br> What is x?

Thepotemich [5.8K]

Answer:

x=-7/6

alternate form-x=-1 1/6

3 0

3 years ago

Find the center and the radius of this equation by completing the

Colt1911 [192]

Answer:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

And solving we got:

$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

$C= (-2,-10)$

$r = \sqrt{4}=2$

Step-by-step explanation:

For this case we have the following equation given:

$x^2 +4x +y^2 -20 y +100=0$

We want to find a general expression given by:

$(x-h)^2 +(y-k)^2 = r^2$

Where the center is (h.k) and the radius is r.

We can begin completing the squares of the equation given and we got:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

And solving we got:

$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

Then we can conclude that the center is:

$C= (-2,-10)$

And the radius would be:

$r = \sqrt{4}=2$

6 0

3 years ago