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3 years ago

What is 42.8 on its standard form???

Mathematics

2 answers:

Lady_Fox [76]3 years ago

8 0

Answer:

42.8 x 10^0

Step-by-step explanation:

A. Standard Form

Ax + By = C.

A, B, C are integers (positive or negative whole numbers)

No fractions nor decimals in standard form.

Traditionally the "Ax" term is positive.

Musya8 [376]3 years ago

4 0

Answer:

$4.28 \times 10^{1}$

Step-by-step explanation:

$42.8 \times 10^0=42.8$

$4.28 \times 10^{1}=42.8$

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Two angles are complementary. The larger angle is 6 more than twice the smaller angle. Write an equation to find the measure of

Tatiana [17]

Let x = the smaller angle

then 2x + 6 = the larger angle

Since they are comlementary, then their sum is 90°

smaller angle + larger angle = 90°

(x) + (2x+6) = 90

3x + 6 = 90

3x = 84

x = 28 (this is the smaller angle)

the larger angle is 2x + 6 = 2(28) + 6 = 56 + 6 = 62

Answer: smaller angle is 28, larger angle is 62

5 0

3 years ago

Greg is saving to buy a tablet that costs $235. He already has $25 saved up. Each week, Greg earns $15 babysitting and $25 as a

Nikitich [7]

Answer:

235=30x-25

Step-by-step explanation:

235+25=30x-25+25

260=30x

260/30=30x/30

x=8.66 or 9 weeks

8 0

3 years ago

What is 46.08 divided by 0.8

TiliK225 [7]

The answer is 5.76...

6 0

3 years ago

Read 2 more answers

I need to know how to graph (15,45)

IgorC [24]

15 is on the X-axis (Horizontal) and 45 is on the Y-axis (Vertical)

5 0

4 years ago

A certain test preparation course is designed to help students improve their scores on the USMLE exam. A mock exam is given at t

bogdanovich [222]

Answer:

The critical value is $T = 4.604$ .

The 99% confidence interval for the average net change in a student's score after completing the course is (6.236, 22.164).

Step-by-step explanation:

The first step to solve this question is finding the sample mean and sample standard deviation:

14,11,18,9,19

Sample mean is sum of all values divided by the number of values. Thus:

$\overline{x} = \frac{14+11+18+9+19}{5} = 14.2$

The sample standard deviation is the square root of the division of the sum of the subtractions squared of each value and the mean, and the number of values. Thus:

$s = \sqrt{\frac{(14-14.2)^2+(11-14.2)^2+(18-14.2)^2+(9-14.2)^2+(19-14.2)^2}{5}} = 3.868$

Confidence interval:

We have the standard deviation for the sample, and so we use the t-distribution to build the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 5 - 1 = 4

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 4 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 4.604.

The critical value is $T = 4.604$ .

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 4.604\frac{3.868}{\sqrt{5}} = 7.964$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 14.2 - 7.964 = 6.236.

The upper end of the interval is the sample mean added to M. So it is 14.2 + 7.964 = 22.164.

The 99% confidence interval for the average net change in a student's score after completing the course is (6.236, 22.164).

8 0

3 years ago